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ipn [44]
2 years ago
7

Which of the three following graphs display the same data?

Mathematics
2 answers:
babymother [125]2 years ago
7 0

Answer:

B

Step-by-step explanation:

Data in II is different

Example:

Sales in March are 71,000 in II, while 73,000 in I and III

Zepler [3.9K]2 years ago
3 0

Answer:

B. I and III

Step-by-step explanation:

I and III both have the same data:

March, 73

April 74

May 78

June 84

July 75

II has different data

March 71

April 72

May 85

June 90

July 60

Since I and III have the exact same data, choice B is the best answer

Hope this helps! :)

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An anthropologist finds that a prehistoric bone contains less than 8.1% of the amount of Carbon-14 the bones would have containe
stealth61 [152]

Answer:

20,944 years

Step-by-step explanation:

The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years.  We are given the k value of .00012.  If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon.  What's left then is 8.1%.  Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal.  We can use the 8.1.  Here's the formula:

N(t)=N_{0} e^{-kt}

where N(t) is the amount left over after the decay occurs, N_{0} is the initial amount, -k is the constant of decay (it's negative cuz decay is a taking away from as opposed to a giving to) and t is the time in years.  Filling in accordingly,

8.1=100e^{-.00012t}

Begin by dividing the 100 on both sides to get

.081=e^{-.00012t}

Now take the natural log of both sides.  Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.

ln(.081)= -.00012t

Take the natual log of .081 on your calculator to get

-2.513306124 = -.00012t

Now divide both sides by -.00012 to get t = 20,944 years

4 0
2 years ago
A cylinder has a base area of 28.2 m2 and a height of 3.1 m. Estimate the volume of the cylinder. A) 31 m3 B) 31 m2 Eliminate C)
Irina18 [472]
The answer can't be C or D because the unit of volume is always cubed. The formula for volume of cylinder is (pi)(r^2)(h) . The pi(r^2) part is the formula for area of a circle which is what the base of the cylinder is. Fortunately the area is already given as 28.2. Plug that into the volume formula and plug in 3.1 for the height and multiply. I get 87.42 and the answer choice B seems to be the closest option
6 0
2 years ago
Read 2 more answers
A bowl is the shape of a hemisphere and made out of thick clay. The diameter of the outside bowl is 44.6 cm. And the diameter of
aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Ive already explained this somebody else asked if you find it you will have the answer

3 0
2 years ago
What value should go in the empty box to complete the calculation for finding the product of 62.834 × 0.45? 62.834 times 0.45 gi
iVinArrow [24]
In this item, we are to supply for the missing term on one side of the equation. The left side is given to be composed of 62.834 x 0.45. The right hand side is given to be composed of 314170 along with a missing entity. 

Translating the given to mathematical expression and letting A be the unknown,
  62.834 x 0.45  = 314170 A

To determine the value of A, divide both sides of the equation by 314170.
             (314170A)/(314170) = (62.834 x 0.45) / 314170
                 A = 0.00009

The missing value is 0.00009 or 9.0 x 10^-5. 
7 0
2 years ago
If g (x) = StartFraction x + 1 Over x minus 2 EndFraction and h(x) = 4 – x, what is the value of (g circle h) (negative 3)? Eigh
brilliants [131]

Answer:

Step-by-step explanation:

Given  g (x) = \frac{x+1}{x-2} and h(x) = 4-x, we are to find (goh)(-3)

First we need to get (goh)(x)

(goh)(x) = g(h(x))\\g(h(x))= g(4-x)\\g(4-x) = \frac{(4-x)+1}{(4-x)-2}\\ g(4-x) =  \frac{5-x}{2-x}\\substitute \ x = -3 \ into \ resulting \ function\\ g(4-x) =  \frac{5-x}{2-x}\\(goh)(-3) =  \frac{5-(-3)}{2-(-3)}\\\\(goh)(-3) =  \frac{8}{5}\\

Hence (goh)(x)\ is \ Eight-fifths

Also given f(x) = x and g(x) = 1/x, we are to find (fog)(x)

(fog)(x) = f(g(x))\\f(g(x)) = f(\frac{1}{x}  )\\ since \ f(x) = x^2, we\ will \ repalce\ x \ with \ \frac{1}{x} \ to \ have;\\ f(\frac{1}{x}  ) =( \frac{1}{x})^2\\\\

f(\frac{1}{x} ) = \frac{1}{x^2}

For the pair of function f(x) = 2/x and g(x) = 2/x

f(g(x)) = f(2/x)

f(2/x) = 2/(2/x)

f(2/x) = 2*x/2

f(2/x) = x

Hence f(g(x)) = x

For the pair of function f(x) = x-2/3 and g(x) = 2-3x

f(g(x)) = f(2-3x)

f(2-3x) = (2-3x-2)/3

f(2-3x) = -3x/3

f(2-3x) = -x

f(g(x)) = -x for the pair of function

For the pair of function f(x) = x/2 - 2 and g(x) = x/2 + 2

f(g(x)) = f(x/2 + 2)

f(x/2 + 2) = f((x+4)/2)

f((x+4)/2) =  [(x+4)/2]/2 - 2

f((x+4)/2) =  (x+4)/4 - 2

find the LCM

f((x+4)/2) =  [(x+4)-8]/4

f((x+4)/2) =  (x-4)/4

Hence f(g(x)) for the pair of function is (x-4)/4

8 0
2 years ago
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