2 years ago

The sum of the measures of two vertical

Mathematics

1 answer:

Gnoma [55]2 years ago

8 0

Answer:

$let \: one \: of \: the \: angles \: be \: x \\ x + x = 44 \\ 2x = 44 \\ x = 22 \degree$

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Elina [12.6K]

we have

$10x^{2} + 40x - 13 = 0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$10x^{2} + 40x =13$

Factor the leading coefficient

$10(x^{2} + 4x) =13$ ----------> the value of A is $10$

Complete the square. Remember to balance the equation by adding the same constants to each side

$10(x^{2} + 4x+4) =13+40$

$10(x^{2} + 4x+4) =53$

Rewrite as perfect squares

$10(x+2)^{2} =53$

$10(x+2)^{2} =53 \\ (x+2)^{2} =\frac{53}{10} \\ \\ x+2=(+/-)\sqrt{\frac{53}{10}} \\ \\ x1=-2+\sqrt{\frac{53}{10}}\\ \\ x2=-2-\sqrt{\frac{53}{10}}$

therefore

the answer is

the value of A is $10$

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enyata [817]

Answer:

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