Answer=1/24
1/3+5/8=
to solve for this, we need the denominators of the fractions to match.
The LCM of 3 and 8 is 24
1/3=8/24
5/8=15/24
8/24+15/24=23/24
Now if we're using 23/24, then only 1/24 is left.
24/24-23/24=1/24
Answer:
La altura de la pirámide es de 8.14 unidades.
Step-by-step explanation:
Hay una pirámide cuadrangular regular cuyas caras laterales forman un ángulo que mide 53º con la base y el área de la superficie lateral es 60. ¿Qué altura tiene?
Dado que el área de superficie lateral = 60
Tenemos
Área del triángulo equilátero = (√3 / 4) × a²
(√3 / 4) × a² = 60
a² = 60 / (√3 / 4) = 80 · √3
a = √ (80 · √3) = 11.77 unidades
La altura inclinada = Altura de la superficie inclinada = a × sin (60) = 11.77 × sin (60)
La altura inclinada = 11.77 × sin (60) = 10.194 unidades
La altura de la pirámide = Altura inclinada × sin (ángulo de caras laterales con la base)
La altura de la pirámide = 10.194 × sin (53) = 8.14 unidades.
La altura de la pirámide = 8.14 unidades.
Answer:
The volume of the cylindrical bucket to the nearest tenth of a cubic centimeter is 12,122.6 cm^3
Step-by-step explanation:
In this question, we are asked to calculate the volume of a cylindrical bucket with height 35cm and a base diameter of 21cm
Mathematically, the volume of the cylinder V can be calculated using the formula;
V = π * r^2 * h
The value of π = 22/7
since D = 21cm, r = D/2 = 21/2 = 10.5cm
Substituting these values, we have
V = 22/7 * 10.5^2 * 35 = 12,122.621
To the nearest tenth of a cubic centimeter is 12,122.6 cm^3
