The area of the figure

The grocery store sells kumquats for $5.00 a pound and Asian pears for $3.25 a pound. Write an equation in standard form for the

FinnZ [79.3K]

Hope this helps but I think the answer is 5k+3.25p=18

6 0

2 years ago

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What is the value of s and the length of side BC if ABCD is a rhombus?

Natali5045456 [20]

Step 1

Find the value of s

we know that

In a Rhombus all sides are congruent

so

$AB=BC=CD=DA$

$AB=9s+29\\CD=10s-16$

equate AB and CD

$9s+29=10s-16\\$

Combine like term

$10s-9s=29+16\\$

$s=45\ units$

The answer Part a) is

the value of s is $45\ units$

Step 2

Find the value of side AB

$AB=9s+29$

substitute the value of s

$AB=9*45+29=434\ units$

Remember that the sides are congruent

$AB=BC=CD=DA$

therefore

the answer Part b) is

The length of the side BC is $434\ units$

4 0

2 years ago

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From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri

Leviafan [203]

Answer:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=201.77$ represent the sample mean

$s=2.41$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =200$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :

Null hypothesis: $\mu = 200$

Alternative hypothesis: $\mu = 200$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0

2 years ago

A square with an area A2 of is enlarged to a square with an area of 25A2. How was the side of the smaller square changed?

makvit [3.9K]

Given:
a square with an area of a² is enlarged to a square with an area of 25a².

The side length of the smaller square was changed when The side length was multiplied by 5.

Area = (1a)² = a²
Area = 1a * 5 = 5a ⇒ (5a)² = 25a²

3 0

2 years ago

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The partial factorization of x2 – 3x – 10 is modeled with algebra tiles. Which unit tiles are needed to complete the factorizati

kkurt [141]

Answer:

(x - 5)(x + 2)

Step-by-step explanation:

x² - 3x - 10 =

= x² + 2x - 5x - 10

= x(x + 2) - 5(x + 2)

= (x - 5)(x + 2)

6 0

2 years ago