Use the FOIL method (First, Outside, Inside, Last)
6r(-8r) = -48r²
6r(-3) = -18r
-1(-8r) = 8r (note: two negatives multiplied together = positive answer)
-1(-3) = 3
-48r² - 18r + 8r + 3
Combine like terms:
-48r² - 18r + 8r + 3
-48r² - 10r + 3
-48r² - 10r + 3 is your answer
hope this helps
Answer:
Linear
For an increase of 1 in the x-value, what is the increase in the y-value? 2
Add all the new budget amounts:
510 + 254 + 295 + 51 + 0 + 100 + 100+ 0 + 100 = 1410
Her monthly total is 1410, which is less than her income of 1700
1700 - 1410 = 290
She has $290 extra each month.
So she can divide that amount by 2 to put an equal amount in each blank category, or add what ever amount less than that into each one.
Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.
