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lyudmila [28]
2 years ago
10

At a cafe, for every 5 sodas sold there are 9 teas sold. What is the ratio of teas sold to sodas sold? A) 5 : 9 B) 9 : 5 C) 9 :

14 D) 14 : 9
Mathematics
2 answers:
frutty [35]2 years ago
7 0
For 5 sodas sold, there are 9 teas sold


the ratio is tea: soda, or 9:5

B) 9:5 is your answer

hope this helps
aliina [53]2 years ago
4 0
The answer would be b. 9:5.

Hope this helps!!
~Kiwi

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A Petri dish is growing bacteria. It starts with 3 cells on day 1, 9 cells on day 2, and continues tripling the number of cells
n200080 [17]

Answer:

243

Step-by-step explanation:

Given that:

Day 1 = 3

Day 2 = 9

After the 2nd day, number of cells continue to triple ;

Day 3 = 9^3

P(t) = 9 * 3^3

P(t) = 9 * 27

= 243

3 0
1 year ago
What are the solutions of the equation x4 + 95x2 – 500 = 0? Use factoring to solve.
VMariaS [17]

Given

The equation in the form

x^{4}+95x^{2}-500 =0

Find the factor of the above equation

To proof

factoring the above equation

we get

x^{4}+100x^{2}-5x^{2}-500 =0\\\\x^{2}(x^{2}+100)-5(x^{2}+100)=0\\\\(x^{2}-5)(x^{2}+100)=0

now sloving the equation we get the value

x² = 5

x² = -100

x =\pm \sqrt{5}\\\\ x=\sqrt{-100}

The factor of the equation is

x=\pm \sqrt{5}\\\\ x= \pm 10i

Hence proved

8 0
1 year ago
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Divide. Round to the nearest tenth.<br><br> .48 divided by 9.23
Kobotan [32]

I believe the answer is 0.1

3 0
1 year ago
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Money Spent on Road Repair A politician wishes to compare the variances of the amount of money spent for road repair in two diff
Mkey [24]

Answer:

(A) Null Hypothesis, H_0 : \sigma_1^{2} =\sigma_2^{2}      {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, H_A : \sigma_1^{2} \neq \sigma_2^{2}      {means that there is a significant difference in the variances of the amounts spent in the two counties}

(B) The F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) The value of the F-test statistic is 0.611.

(D) We conclude that there is no significant difference in the variances of the amounts spent in the two counties.

Step-by-step explanation:

We are given that a politician wishes to compare the variances of the amount of money spent on road repair in two different counties.

The data are given here below;

County A              County B

s1 = $11,596         s2 = $14,837

n1 = 15                     n2 = 18

Let \sigma_1^{2} = variances of the amounts spent in County A.

\sigma_2^{2} = variances of the amounts spent in County B.

(A) So, Null Hypothesis, H_0 : \sigma_1^{2} =\sigma_2^{2}      {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, H_A : \sigma_1^{2} \neq \sigma_2^{2}      {means that there is a significant difference in the variances of the amounts spent in the two counties}

The test statistics that would be used here <u>Two-sample F-test statistics </u>distribution;

                             T.S. =  \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ F__n_1_-_1,_ n_2_-_1

where, s_1 = sample standard deviation for County A = $11,596

s_2 = sample standard deviation for County B = $14,837

n_1 = sample size for County A = 15

n_2 =  sample size for County B = 18

(B) Now at 0.05 level of significance, the F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) So, <u><em>the test statistics</em></u>  =  \frac{11,596^{2}  }{14,837^{2} } \times 1  ~  F__1_4,_ 1_7

                                     =  0.611

The value of the F-test statistic is 0.611.

Now, as we can see that our test statistics lie within the range of critical values of F, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

(D) Therefore, we conclude that there is no significant difference in the variances of the amounts spent in the two counties.

7 0
2 years ago
Dario increased his savings from $350 to $413. While Monica increased her savings from $225 to $270. Who had a higher percent of
Anettt [7]
The percentage in increase can be calculated as follows:
% of increase = (difference between new and old amounts / old value) *100

For Dario:
difference in values = 413 - 350 = 63
% of increase = (63/350)*100 = 18%

For Monica:
difference in values = 270 - 225 = 45
% of increase = 20%

Therefore,
Monica has higher percent of increase.
The difference in percents = 20% - 18% = 2%
4 0
2 years ago
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