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victus00 [196]
1 year ago
8

Mary is paid $12 per hour at her weekend part-time job. She earns an average of $132 each weekend, but her earnings can vary by

$36. Which inequality represents the number of hours, h, Mary could work in one weekend? A. h ≤ 8 or h ≥ 14 B. h ≤ 3 or h ≥ 11 C. 3 ≤ h ≤ 11 D. 8 ≤ h ≤ 14
Mathematics
1 answer:
RSB [31]1 year ago
8 0

Given:

Mary is paid $12 per hour at her weekend part-time job.

She earns an average of $132 each weekend, but her earnings can vary by $36.

To find:

The inequality for number of hours.

Solution:

Let h be the number of hours Mary could work in one weekend.

Total earning for h hours = $12h

She earns an average of $132 each weekend, but her earnings can vary by $36. So,

132-36\leq \text{Total earning}\leq 132+36

96\leq \text{Total earning}\leq 168

96\leq 12h\leq 168

Divide all sides by 12.

\dfrac{96}{12}\leq \dfrac{12h}{12}\leq \dfrac{168}{12}

8\leq h\leq 14

Therefore, the correct option is D.

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Which of the following are exterior angles? Check all that apply.
Marina86 [1]

Answer:

A

C

D

E

Step-by-step explanation:

Exterior angles can be described as the angles that are formed between the side of a polygon and the extended adjacent side of the polygon.

Or an exterior angle is the angle that is not inside the triangle formed.

The angles inside the triangle are interior angles.

Exterior angles are :

2

3

4

6

Interior angles are :

1

5

6 0
1 year ago
Using the midpoint method, find the cross-price elasticity of demand for FedEx and UPS overnight shipping if the price of FedEx
IrinaK [193]

Answer:

Cross price elasticity using midpoint method = 0.56

Step-by-step explanation:

Using the mid-point method

Cross-price Elasticity of Demand = <u>% change in Quantity demanded of UPS</u>

                                                          % change of price of FedEx

%change in Quantity demanded of UPS

using Mid-point method                          = <u> Q2-Q1           </u>  × 100

                                                                     (Q1+Q2)÷ 2

                                      = <u>1.3-1.2           </u>   × 100

                                        (1.2+1.3)÷2

                                     = <u>0.1      </u> × 100

                                       1.25

                                     = 8%

% change in price of FedEx

using midpoint method    =<u> P2-P1            </u>× 100

                                             (P1+P2)÷ 2

                                          =<u> 75-65           </u>× 100

                                            (65+75)÷2

                                          =<u> 10  </u>   × 100

                                             70

                                          = 14.28%

Cross-price Elasticity of Demand =  8% ÷ 14.28%

using midpoint method                = 0.56

             

6 0
1 year ago
A basic cellular package costs $20 per month for 60 minutes of calling, with an additional charge of $0.20/min beyond that time.
Anika [276]

Answer: you can use 260 min, 60 min at a fixed price ($20) and extra 200.

Step-by-step explanation:

C(x) = 20 + 0.20(x − 60)

C(x) ≤ 60

20 + 0.20(x − 60) ≤ 60

0.20(x − 60) ≤ 60 - 20

0.20x - 12 ≤ 40

0.20x ≤ 40 + 12

0.20x ≤ 52

x ≤ 52/0.2

x ≤ 260

This way, you can use 260 min, 60 min at a fixed price ($20) and extra 200.

7 0
2 years ago
Barbara drives between Miami, Florida, and West Palm Beach, Florida. She drives 50 mi in clear weather and then encounters a thu
NeX [460]

Distance traveled in clear weather = 50 miles

Distance traveled in thunderstorm = 15 miles

Let speed in clear weather = x

⇒ Speed in thunderstorm = x-20

Total time taken for trip = 1.5 hours

We need to determine average speed in clear weather (i.e. x) and average speed in the thunderstorm (i.e. x-20 ).

Total time taken for trip = Time taken in clear weather + Time taken in thunderstorm

⇒ Total time taken for trip = \frac{Distance covered in clear weather}{Speed in clear weather} + \frac{Distance covered in thunderstorm}{Speed in thunderstorm}

⇒ 1.5 = \frac{50}{x} + \frac{15}{x-20}

⇒ 1.5 = \frac{50(x-20)+15(x)}{(x)(x-20)}

⇒ 15*x*(x-20) = 10*[50*(x-20)+15*x]

⇒ 15x² - 300x = 500x - 10,000 + 150x

⇒ 15x² - 300x = 650x - 10,000

⇒ 15x² - 950x + 10,000 = 0

⇒ 3x² - 190x + 2,000 = 0

The above equation is in the format of ax² + bx + c = 0

To determine the roots of the equation, we will first determine 'D'

D = b² - 4ac

⇒ D = (-190)² - 4*3*2,000

⇒ D = 36,100 - 24,000

⇒ D = 12,100

Now using the D to determine the two roots of the equation

Roots are: x₁ = \frac{-b+\sqrt{D}}{2a} ; x₂ = \frac{-b-\sqrt{D}}{2a}

⇒ x₁ = \frac{-(-190)+\sqrt{12,100}}{2*3} and x₂ = \frac{-(-190)-\sqrt{12,100}}{2*3}

⇒ x₁ = \frac{190+110}{6} and x₂ = \frac{190-110}{6}

⇒ x₁ = \frac{300}{6} and x₂ = \frac{80}{6}

⇒ x₁ = 50 and x₂ = 13.33

So speed in clear weather can be 50 mph or 13.33 mph. However, we know that in thunderstorm was 20 mph less than speed in clear weather.

If speed in clear weather is 13.33 mph then speed in thunderstorm would be negative, which is not possible since speed can't be negative.

Hence, the speed in clear weather would be 50 mph, and in thunderstorm would be 20 mph less, i.e. 30 mph.

7 0
2 years ago
What is not a pair of equivalent fractions for 5/8 and 1/2
n200080 [17]
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18 
15/30: 5/10 OR 1/2 
45/60: 8/12 OR 4/6 

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number. 

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8. 
2/5 and 1/2: 2/5 and 2.5/5 
9/9 and 5/7: 9/9 and ~5.7/9 

Rewrite each in simple form: Find greatest common factor and divide. 

9/54: 1/6 
20/40: 1/2 
100/110: 10/11 

Are these fractions equivalent? 
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole. 


In what situation can you use multiplication to find equivalent fractions? 
I'm sorry but I do not understand this question. 
</span>Source(s):<span>I hope I  helped, seeing as I have graduated with a math degree.</span>
7 0
2 years ago
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