have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a h
2 answers:
Answer:
0.2239
Step-by-step explanation:
Given that you have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a hat, then from that hat, I choose 3 balls, without replacing the balls between selections.
Either I or II hat can be selected.
Prob of selecting any one hat = 0.5
After selecting I hat, selecting 3 balls can be done in 15C3 ways and from II hat it can be done in 10C3 ways.
total no of ways of selecting 3 balls = (10+15)C3 = 2300
Probability required
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Answer:
a). Cost of 44 pupils = $14265
b). Least number of pupils = 31
Step-by-step explanation:
The given question is incomplete; here is the complete question.
The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.
(a) Find the cost when there are 44 pupils.
(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?
Let the equation representing the total cost of maintaining a school is,
C = ax + b
Where C = Total cost of maintaining a school
a = Fee per pupil
b = Fixed running cost
x = number of pupils
a). Cost of 50 pupils = $15705
Equation will be,
15705 = 50a + b -------(1)
Cost of 40 pupils = $13305
Equation will be,
13305 = 40a + b --------(2)
By subtracting equation (2) from equation (1),
15705 - 13305 = (50a + b) - (40a + b)
2400 = 10a
a = 240
From equation (1),
b = 3705
Equation representing the total cost will be,
C = 240x + 3705
If x = 44
C = 240(44) + 3705
C = $14265
b). If the fee per pupil 'a' = $360
Let the number of pupils = p
Total fee of 'p' pupils = $360p
Total cost to run the school will be = 3705 + 240p
For the school not to be in the loss,
360p ≥ 3705 + 240p
360p - 240p ≥ 3705
120p ≥ 3705
p ≥
p ≥ 30.875
Therefore, to run the school without loss, number pupils should be at least 31.
Answer:
Reasonable estimation for constant of variation is 0.25 kWh per day.
Step-by-step explanation:
We are given the following information in the question:
- The graph represents the function where electricity usage.
- Electricity usage in kilowatts per hour of a clock radio varies directly with the number of days.
- The x-axis shows the number of days and usage in kilo-watt per hour is showed on the y-axis.
- Some coordinates of the graph are: (0,0), (2,0.5) and (6,1.5)
Formula for constant of variation:
Putting the values from the coordinates (2,0.5) and (6,1.5), we get:
Hence, reasonable estimation for constant of variation is 0.25 kWh per day.