have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a h
2 answers:
Answer:
0.2239
Step-by-step explanation:
Given that you have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a hat, then from that hat, I choose 3 balls, without replacing the balls between selections.
Either I or II hat can be selected.
Prob of selecting any one hat = 0.5
After selecting I hat, selecting 3 balls can be done in 15C3 ways and from II hat it can be done in 10C3 ways.
total no of ways of selecting 3 balls = (10+15)C3 = 2300
Probability required
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Answer:
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Answer:
0 and 5 minutes
Step-by-step explanation:
Median is the middle observation of given data. It can be found by following steps:
Arranging data in ascending or descending order.
Taking the average of middle two value if the total number of observation is even, and this average is our median.
or, if we odd number of observation then the most middle value is our median.
The mode is the observation which has a high number of repetitions (frequency).
We have given 8 numbers and we have to find the other two numbers a minute late for each bus to arrive at the bus stop.
Also, we have given the median and mode of all 10 buses i.e. 3.5 and 0 respectively.
Since the mode is 0, so the frequency of 0 must be greater than 2 times and less than or equal to 4 times.
The frequency of 0 is 4 is not possible as then we didn't get a median 3.5 then.
So the frequency of 0 is 3.
Hence one of number is 0 in two unknown number of a minute late for each bus arrive at the bus stop.
Now, we have the number of minutes late for each bus after arranging them in ascending order is: 0 0 0 2 2 6 8 8 9
For getting a median 3.5 we must have a number between 2 and 6. Let it be x then:
⇒x = 5
Hence the number of minutes late for each bus is: 0 0 0 2 2 5 6 8 8 9
Thus, 0 and 5 are minutes late for the two-afternoon buses.