have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a h
2 answers:
Answer:
0.2239
Step-by-step explanation:
Given that you have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a hat, then from that hat, I choose 3 balls, without replacing the balls between selections.
Either I or II hat can be selected.
Prob of selecting any one hat = 0.5
After selecting I hat, selecting 3 balls can be done in 15C3 ways and from II hat it can be done in 10C3 ways.
total no of ways of selecting 3 balls = (10+15)C3 = 2300
Probability required
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Answer:
Student A and Student B both answered 2 questions correctly.
See explanation below
Step-by-step explanation:
Note: that answers in the form:
ARE ALL EQUIVALENT.
First of all, 4/5 is equivalent to 0.8 if we do long division.
and 19/20 is 0.95 if we do long division.
Now, <u>Student A:</u>
Both of the fractions are correct and the negative sign is equivalent and makes the answer correct, so both are correct.
For <u>Student B:</u>
Similarly, both answers are correct for this student as well, looking at the equivalence we showed first.
Also, "-" (negative) in front of the parenthesis and inside parenthesis here doesn't matter.
Hence,
Student A and Student B both answered 2 questions correctly.