One morning, eight buses arrive at a bus stop.
2 answers:
Answer:
0 and 5 minutes
Step-by-step explanation:
Median is the middle observation of given data. It can be found by following steps:
Arranging data in ascending or descending order.
Taking the average of middle two value if the total number of observation is even, and this average is our median.
or, if we odd number of observation then the most middle value is our median.
The mode is the observation which has a high number of repetitions (frequency).
We have given 8 numbers and we have to find the other two numbers a minute late for each bus to arrive at the bus stop.
Also, we have given the median and mode of all 10 buses i.e. 3.5 and 0 respectively.
Since the mode is 0, so the frequency of 0 must be greater than 2 times and less than or equal to 4 times.
The frequency of 0 is 4 is not possible as then we didn't get a median 3.5 then.
So the frequency of 0 is 3.
Hence one of number is 0 in two unknown number of a minute late for each bus arrive at the bus stop.
Now, we have the number of minutes late for each bus after arranging them in ascending order is: 0 0 0 2 2 6 8 8 9
For getting a median 3.5 we must have a number between 2 and 6. Let it be x then:
⇒x = 5
Hence the number of minutes late for each bus is: 0 0 0 2 2 5 6 8 8 9
Thus, 0 and 5 are minutes late for the two-afternoon buses.
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Answer:
a) 0.05
b) 0.9826
c) 0.000039308
Step-by-step explanation:
a)
b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.
Hence,
c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.
As a result,
Practically 0