Answer:
t(d) = 0.01cos(5π(d-0.3)/3)
Step-by-step explanation:
Since we are given the location of a maximum, it is convenient to use a cosine function to model the torque. The horizontal offset of the function will be 0.3 m, and the horizontal scaling will be such that one period is 1.2 m. The amplitude is given as 0.01 Nm.
The general form is ...
torque = amplitude × cos(2π(d -horizontal offset)/(horizontal scale factor))
We note that 2π/1.2 = 5π/3. Filling in the given values, we have ...
t(d) = 0.01·cos(5(d -0.3)/3)
The answer is 2.95 × 10²³ atoms
Atomic mass is 200.59 g.
So, 1 mole has 200.59 g. Let's calculate how many moles have 98.3 g:
1M : 200.59g = x : 98.3g
x = 98.3 g * 1 M : 200.59 g = 0.49 M
To calculate this, we will use Avogadro's number which is the number of units (atoms, molecules) in 1 mole of substance:
6.023 × 10²³ atoms per 1 mole
<span>How many atoms are in 0.49 mole:
</span>6.023 × 10²³ atoms : 1M = x : 0.49M
x = 6.023 × 10²³ atoms : 1M * 0.49M = 2.95 × 10²³ atoms
The corresponding sides of the model and the actual bridge are in proportion because the two solids are similar.
The scale factor from the model to the actual bridge is 5/25 = 6/30 = 8/40 = 1/5.
Answer: 1/5