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Dmitrij [34]
2 years ago
12

Select the statement that is true. Group of answer choices There are integers s and t such that 2=102⋅s+72⋅t . here are integers

s and t such that 8=102⋅s+72⋅t . There are integers s and t such that 1=102⋅s+72⋅t . There are integers s and t such that 6=102⋅s+72⋅t .
Mathematics
1 answer:
LekaFEV [45]2 years ago
3 0

Answer:

Step-by-step explanation: true

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19x+rx=-37+w <br><br><br> solve for x
ipn [44]

Factor the left side:-

x (19 + r) = -37 + w

x = ( -37 + w) / (19 + r) Answer


3 0
2 years ago
Read 2 more answers
Which data set is least Likely to resemble a normal distribution?<br> Look at picture
kicyunya [14]

Answer: B) The heights of girls who live on a certain street in the city of Buffalo

Every answer choice starts with "the heights of all 14-year-old girls who", so we can ignore that part. Choice A describes the largest population while choice B describes the smallest population. In other words, choice A is very general and broad, while choice B is very specific and narrow. The more specific you get and the smaller the population is, the less likely its going to be normally distributed.

4 0
2 years ago
Explain what it means to have a correlation in a scatterplot.
Karo-lina-s [1.5K]

Answer:

A correlation exists in a scatter plot if there is a general trend in the outputs as inputs increase. If the outputs generally increase in value, then there is a positive correlation. If the outputs generally decrease in value, then there is a negative correlation. 

3 0
2 years ago
Read 2 more answers
According to an informal poll in Glenview 1/3
Talja [164]

Answer:

Percent form: 41.65%

Fraction form: \frac{833}{2000}

Step-by-step explanation:

33% of men support John Smith.

67% of women support John Smith.

Lets say, for instance, that there are 20 polled individuals -- 10 women and 10 men.

However, since 1.5 times as many men voted as women, we have to apply our poll to 15 men and 5 women.

33% of the 15 men makes 5 men who voted for Smith and 10 who did not.

67% of the 5 women makes 3.33 women who voted for Smith and 1.67 who did not.

Add these numbers together.

8.33 total voters were cast for John Smith, while 11.67 were not.

Now, divide 8.33 by 20 and multiply by 100 to obtain a percentage.

\frac{8.33}{20} \\.4165\\41.65

41.65% of voters voted for John Smith according to the results of the poll.

7 0
2 years ago
A math teacher tells her students that eating a healthy breakfast on a test day will help their brain function and perform well
kogti [31]

Answer:

Step-by-step explanation:

Hello!

To test the claim that eating a healthy breakfast improves the performance of students on their test a math teacher randomly asked 46 students what did they have for breakfast before they took the final exam and classified them as:

<u>Group 1</u>: Ate healthy breakfast

X₁: Number of students that ate a healthy breakfast before the exam and earned 80% or higher.

n₁= 26

<u>Group 2: </u>Did not eat healthy breakfast

X₂: Number of students that did not eat a healthy breakfast before the exam and earned 80% or higher.

n₂= 20

After the test she counted the number of students that got 80% or more in the test for each group obtaining the following sample proportions:

p'₁= 0.50

p'₂= 0.40

The parameters of study are the population proportions, if the claim is true then p₁ > p₂

And you can determine the hypotheses as

H₀: p₁ ≤ p₂

H₁: p₁ > p₂

α: 0.05

Z= \frac{(p'_1-p'_2)-(p_1-p_2)}{\sqrt{p'(1-p')[\frac{1}{n_1} +\frac{1}{n_2}] } } }≈N(0;1)

pooled sample proportion: p'= \frac{x_1+x_2}{n_1+n_2} =\frac{13+8}{46} = 0.46

Z_{H_0}= \frac{(0.5-0.4)-0}{\sqrt{0.46(1-0.46)[\frac{1}{26} +\frac{1}{20}] } } }= 0.67

p-value: 0.2514

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value: 0.2514 is greater than the significance level 0.05, the test is not significant.

At a 5% significance level you can conclude that the population proportion of math students that obtained at least 80% in the test and had a healthy breakfast is equal or less than the population proportion of math students that obtained at least 80% in the test and didn't have a healthy breakfast.

So having a healthy breakfast doesn't seem to improve the grades of students.

I hope this helps!

5 0
2 years ago
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