Answer:
(3x - 4)(8x - 3)
Step-by-step explanation:
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 24 × 12 and sum = - 41
The required factors are - 32 and - 9
Use these factors to split the x- term
24x² - 32x - 9x + 12 ( factor the first/second and third/fourth terms )
= 8x(3x - 4) - 3(3x - 4) ← factor out (3x - 4) from each term
= (3x - 4)(8x - 3) ← in factored form
Answer:
t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.
Step-by-step explanation:
100 = 5 * 10^(0.3t), solve for t
Divide both sides by 5:
20 =10^(0.3t)
Take the log of both sides:
0.3t =log(20)
Divide both sides by 0.3:
Multiply the RHS by 10 / 10
t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.
In statistics, the amount of degrees of freedom is
the quantity of values in the final computation of a statistic that are free to
differ. In this case, you can get the answer by adding the number of bags
and subtracting 1.
So in computation, this would look like: 3 + 2 + 1 + 2 - 1 =
7
Therefore, 7 is the degrees of freedom.
Answer:
1.25x + 1.5y=25
Step-by-step explanation:
let the number of lip balms that can be bought be x and the notebooks be y then their total cost is 1.25x + 1.5y. The total $25 there for the equation becomes 1.25x + 1.5y=25.
Answer:
Required equation 
The height of statue of liberty is 93 meters.
Step-by-step explanation:
Given : Howard has a scale model of the Statue of Liberty. The model is 15 inches tall. The scale of the model to the actual statue is 1 inch : 6.2 meters.
To find : Which equation can Howard use to determine x, the height in meters, of the Statue of Liberty?
Solution :
The model is 15 inches tall.
The scale of the model to the actual statue is 1 inch : 6.2 meters.
Let x be the height in meters of the Statue of Liberty.
According to question, required equation is

Cross multiply,


Therefore, the height of statue of liberty is 93 meters.