Given:
Total number of girls in her class = 16
Total number of boys in her class = 14
To find:
The number of different ways of choosing one girl and one boy.
Solution:
We have,
Total number of girls = 16
Total number of boys = 14
So,
Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
Now, number of different ways of choosing one girl and one boy is

Therefore, the required number of different ways is 224.
The answer is:
1- A line of symmetry will connect a vertex and a midpoint of an opposite side.
2- It has
-fold symmetry.
The explanation for this answer is shown below:
1- By definition, a line of symmetry is an imaginary line that divides a figure into two equal images or equal halves. If you connect a vertex and a midpoint of an opposite side of an heptagon by drawing a line, you will obtain two equal halves.
2- An heptagon has seven vertices, therefore, based on the information mentioned above, it has
-fold symmetry.
The answer
ellipse main equatin is as follow:
X²/ a² + Y²/ b² =1, where a≠0 and b≠0
for the first equation: <span>x = 3 cos t and y = 8 sin t
</span>we can write <span>x² = 3² cos² t and y² = 8² sin² t
and then </span>x² /3²= cos² t and y²/8² = sin² t
therefore, x² /3²+ y²/8² = cos² t + sin² t = 1
equivalent to x² /3²+ y²/8² = 1
for the second equation, <span>x = 3 cos 4t and y = 8 sin 4t we found
</span>x² /3²+ y²/8² = cos² 4t + sin² 4t=1
Answer:
Hello your question is incomplete attached below is the complete question
Ix = 0 Ux = 
Iz = 0 Uz = 
Iy = 5 Uy = 10
Step-by-step explanation:
Ix = 0 Ux = 
Iz = 0 Uz = 
Iy = 5 Uy = 10
attached below is the detailed solution