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AlexFokin [52]
2 years ago
7

The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the w

idth of the poster. What are the dimensions of the poster?
Mathematics
2 answers:
Dafna1 [17]2 years ago
7 0
A= l×w
296 = 1.5l × w

You should get 20 at the end
Alex787 [66]2 years ago
4 0
Hey there,

Your question states: <span>The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the width of the poster. What are the dimensions of the poster? </span>

l= 16 \ x  \ 1.25 = 20  in

Your correct answer would be \boxed{20}

Hope this helps.
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Jenna concludes that (4,9) is the solution to the system of these two equations. which of the following justifies her conclusion
nalin [4]

<u><em>Answer:</em></u>

a. The point (4,9) appears in both tables

<u><em>Explanation:</em></u>

<u>Note:</u> This question can be solved without the need of the tables

<u>A solution of a system of equations</u> is defined as a point (or set of points) that satisfy both equations

<u>This means that,</u> this point should belong to all the equations in the system

Now, a table is used to show a set of points that belong to a certain line

This means that, all vales in the table belong to the line they represent

<u>Since the point (4,9) appears in both tables</u>, therefore, it belongs to both lines and, therefore, is a solution to the system of equations consisting of these two lines

Hope this helps :)

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2 years ago
A restaurant wants to study how well its salads sell. The circle graph shows the sales over the past few days. If 10 of the sala
vova2212 [387]
40%=10
80%=20
100%=25
answer is 25
5 0
2 years ago
Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.
olya-2409 [2.1K]
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
7 0
2 years ago
Read 2 more answers
Each function below describes how something changes. Use the description to determine which function(s) describe exponential gro
cestrela7 [59]

Answer: E. The population decreased by 11% each year.

Step-by-step explanation: In A, the pollution increases at a constant rate, but in a linear way, in other words in each day, the pollution increases 10 grams; The same goes for C: ice "grows" a few milimeters each day; In D, as volume is calculated by the multiplication of π and its radius, the increase in the volume is still linear. In B, the proportionality is related to the power of the turbine not the growth or decay of it. In E, a population grows or decreases in a form of A=A₀(1±r)^t. In this case: A = A₀ (1-0.11)^t.

In conclusion, the function that better describes an exponential growth or decay is the decrease of a population.

6 0
2 years ago
Consider the continuous random variable X, which has a uniform distribution over the interval from 20 to 28.
anastassius [24]

Answer:

a) The probability distribution is f(x) = \frac{1}{8}

b) 0.5 = 50% probability that X will take on a value between 21 and 25.

c) 0.25 = 25% probability that X will take on a value of at least 26.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{a - x}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

Uniform distribution over the interval from 20 to 28.

This means that a = 20, b = 28

a. What’s the probability density function?

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b - a}

In this question:

f(x) = \frac{1}{28 - 20} = \frac{1}{8}

b. What’s the probability that X will take on a value between 21 and 25?

P(21 \leq X \leq 25) = \frac{25 - 21}{28 - 20} = \frac{4}{8} = 0.5

0.5 = 50% probability that X will take on a value between 21 and 25.

c. What’s the probability that X will take on a value of at least 26?

P(X > 26) = \frac{28 - 26}{28 - 20} = \frac{2}{8} = 0.25

0.25 = 25% probability that X will take on a value of at least 26.

4 0
2 years ago
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