All categories

2 years ago

If on a scale drawing 15 feet are represented by 10 inches then a scale of 1/10 inch represents how many feet

Mathematics

1 answer:

GenaCL600 [577]2 years ago

3 0

A scale of $\frac{1}{10}$ inches will represent $\frac{3}{20}$ feet.

Step-by-step explanation:

According to scale drawing;

15 feet = 10 inches

1 inch = $\frac{15}{10}=\frac{3}{2}\ feet$

A scale of $\frac{1}{10}$ inch will represent;

Multiplying both sides by

$\frac{1}{10}*1=\frac{3}{2}*\frac{1}{10}\\\\\frac{1}{10}\ inches = \frac{3}{20}\ feet$

A scale of $\frac{1}{10}$ inches will represent $\frac{3}{20}$ feet.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

You might be interested in

219.836−78.618 please hurry!!!!!!!!!!!!!

Sonja [21]

Answer:

141.218

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

1. Write 3,876,943,000 using scientific notation.

Sunny_sXe [5.5K]

Answer:

3.876943x10^9

7.317x10^-4

Step-by-step explanation:

3,876,943,000

Put the decimal at the end

3,876,943,000.

Move it so only 1 number is before the decimal

3.876943000

We moved it 9 places, so that is the exponent

We moved it to the left, so the exponent is positive

The three zeros at the end can be dropped because they are the last numbers to the right of the decimal

3.876943x10^9

0.0007317

Move it so only 1 number is before the decimal

00007.317

We moved it 4 places, so that is the exponent

We moved it to the right, so the exponent is negative

The four zeros at the left can be dropped because they are the last numbers to the left of the whole number

7.317x10^-4

8 0

2 years ago

A right triangle has legs of length 4x and 20x. What is an expression for the hypotenuse of the right triangle

kherson [118]

Answer:

$4x\sqrt{26}$ .

Step-by-step explanation:

Given information:

$Leg_1=4x$

$Leg_2=20x$

According to the Pythagoras theorem,

$(hypotenuse)^2=(Leg_1)^2+(leg_2)^2$

Using Pythagoras theorem, we get

$(hypotenuse)^2=(4x)^2+(20x)^2$

$(hypotenuse)^2=16x^2+400x^2$

$(hypotenuse)^2=416x^2$

Taking square root on both sides.

$hypotenuse=\sqrt{416x^2}$

$hypotenuse=4x\sqrt{26}$

Hence, the expression of the hypotenuse is $4x\sqrt{26}$ .

5 0

2 years ago

Tanisha and Neal are simplifying the expression . They each began the same way. Tanisha’s Work Neal’s Work Which statements are

valentina_108 [34]

Answer:

The correct simplified answer is $\frac{1}{8} \left (\frac{x}{ y} \right )^{8}$ or $\frac{x^8}{81\cdot y^8}$

Step-by-step explanation:

Here we have the expression as

$\left (\frac{(x^4)(y^{-5})}{3(x^2)(y^{-3})} \right )^{4}$

Tanisha's work

$\left (\frac{(x^4)(y^{-5})}{3(x^2)(y^{-3})} \right )^{4} = \left (\frac{(x^2)(y^{-2})}{3} \right )^{4}$

Neal's work is

$\left (\frac{(x^4)(y^{-5})}{3(x^2)(y^{-3})} \right )^{4} = \left (\frac{(x^{16})(y^{-20})}{3^4(x^8)(y^{-12})} \right )$

The correct simplified answer is $\frac{x^8}{81\cdot y^8}$ .

which can also be expressed as

$\frac{1}{8} \left (\frac{x}{ y} \right )^{8}$

Both form represent simplified forms of the original equation.

8 0

2 years ago

Read 2 more answers

The life, in years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o

Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

$\bf P(X$

So, the probability that a switch fails in the first year is

$\bf P(X$

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and

$\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}$

where

$\bf \binom{100}{k}$ equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

$\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999$

3 0

2 years ago