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Genrish500 [490]
2 years ago
5

Barbara is 142 cm tall this is 2 cm less than 3 times her height at birth find her heaight at birth

Mathematics
1 answer:
FrozenT [24]2 years ago
3 0
142/3= 47.333-2 =45.333
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Find the hcf of 144 and 180. if it is expressed in the form 13m-3, find the value of m​
BaLLatris [955]

Answer:

Step-by-step explanation:

To find the HCF of 144 and 180

By using product of prime method

Firstly express 144 as a product of it prime and express 180 as a product of it prime

140=2×2×2×2×3×3

180=2×2×3×3×5

Common factor =2×2×3×3

36

in term of m

m=36

13m-3

To find m

Substitute for m when m=36

13(36)-3=

465

8 0
2 years ago
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What dose 0.07x1.22 eaqual
iogann1982 [59]
0.07 * 1.22

Is equal to 0.0854
4 0
2 years ago
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Rachel, Adam, Michelle, Hannah, and James are going to the movies. They have $65 to spend on tickets and snacks. Each movie tick
Ann [662]

Answer:

1. By substitution property of inequality

5(9.5)+4.5\leq65

2. By using multiplication  in equality then we get

47.5+4.5x\leq65

3. The five friends will have 3 snacks to split.

Step-by-step explanation:

Given

Five friends have total money= $65

Cost of each movie ticket= $9.50

Cost of each snack item= $4.50

Let ,five friends have total snacks = x

Total movie tickets=5

Because total number of friends=5

The inequality expressionis given by

I Step: 5(9.5)+4.5x\leq 65

Reason: By using substitution property of inequality

47.5+4.5x\leq 65[/tex2. Step :[tex]4.5x[tex]\leq65-47.5[/tex]

4.5x\leq 17.5  ( by subtarction 47.5  from both sides)

x\leq \frac{17.5}{4.5}   ( by dividing 4.5 on both sides )

<h3>x\leq 3.889  (by simplication)</h3><h3>x=3</h3>

Because they can buy maximum 3 snacks .

Beacause the number of snacks is natural number so we can't take in rational numbers.

<h3>Hence, the five friends will have 3 snacks to split.</h3>

6 0
2 years ago
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According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 –
elena55 [62]

Answer:


Step-by-step explanation:

Given is an algebraic polynomial of degree 5.

g(x) = 3x^5-2x^4+9x^3-x^2+12\\

Here leading term is p=3 and constant term is q =12

Factors of p are ±1,±2,±3

Factors of q are \frac{±1,±2,±3,±4,±6,±12} \\

Possible forms of p/q will be the same for any other polynomial of degree 5 with leading term =3 and constant term = 12

Hence any other polynomial

g(x) = 3x^5+ax^4+bx^3+cx^2+12

will have same possible zeroes of p/q, when a,b,c are rational.

Hence any polynomial of this type would have the same possible rational roots.

7 0
2 years ago
Millie has a box of 1 hundred cubes. She also has a bag of 70 cubes. How many trains of 10 cubes can she make?
ANTONII [103]
She has a total of 170 cubes

170/10=17 trains
7 0
2 years ago
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