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Genrish500 [490]
1 year ago
5

Barbara is 142 cm tall this is 2 cm less than 3 times her height at birth find her heaight at birth

Mathematics
1 answer:
FrozenT [24]1 year ago
3 0
142/3= 47.333-2 =45.333
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The information below represents the cost of Cody's home ownership. What is his average monthly expenditure related to his home?
azamat
Let's calculate all expenses per month

a) Mortgage $1,255 →→→→→→→→→ =  $1,255 per month
b)Taxes $2,881 per year →→  $2,881/12 = $240.083  per month
c) insurance $156 →→→→→→→→→→  =$156 per month 
d) HOA fees $320 per year→→→=$320/12 = $ 26.66 per month 
e)utilities $475→→→→→→→→→→→→→=$475

Average monthly expenditure: a) + b) + c) + d) = $2,152.75 

4 0
2 years ago
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The musical note E can be modeled by the function, y = asin(1320πx), where a = 1 and x is the time in seconds. Playing note E on
Andrej [43]

Answer:

Its NOT C.   Its NOT Let a > 0 and a < 1. Try A.

Step-by-step explanation:

4 0
2 years ago
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3) Margarita manejó 429 km: 42 en la ciudad y el resto, en la autopista.
12345 [234]

Answer:

Margarita gastó <u>$40.43.</u>

Step-by-step explanation:

Tenemos la siguiente información.

<u>km recorridos por Margarita</u>

42 km - ciudad

387 km - autopista

<u>Rendimiento del carro</u>

1 galon cada 28 km - ciudad

1 galon cada 36 km - autopista

Hacemos el siguiente factor de conversión

<u>Ciudad</u>

42 km \times \frac{1\: galon}{28\: km}=1.5\: galones

<u>Autopista</u>

387 km \times \frac{1\: galon}{36\: km}=10.75\: galones

Ahoa, se sabe que 1 galon cuesta $3.30. Por lo tanto, el costo de viaje será:

Total galones = 1.5 + 10.75 = 12.25 galones

Total costo = 3.30*12.25 = $40.43.

Espero te haya servido!

4 0
1 year ago
Aubree invested $8,300 in an account paying an interest rate of 2.2% compounded quarterly. Assuming no deposits or withdrawals a
Triss [41]

Answer:

$25,735.03

Step-by-step explanation:

I plugged your numbers into the really big formula

7 0
2 years ago
Read 2 more answers
Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

3 0
2 years ago
Read 2 more answers
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