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aev [14]
2 years ago
10

Howard has a scale model of the Statue of Liberty. The model is 15 inches tall. The scale of the model to the actual statue is 1

inch : 6.2 meters. Which equation can Howard use to determine x, the height in meters, of the Statue of Liberty?
Mathematics
1 answer:
sergiy2304 [10]2 years ago
4 0

Answer:

Required equation \frac{1}{6.2}=\frac{15}{x}

The height of statue of liberty is 93 meters.

Step-by-step explanation:

Given : Howard has a scale model of the Statue of Liberty. The model is 15 inches tall. The scale of the model to the actual statue is 1 inch : 6.2 meters.

To find : Which equation can Howard use to determine x, the height in meters, of the Statue of Liberty?

Solution :

The model is 15 inches tall.

The scale of the model to the actual statue is 1 inch : 6.2 meters.

Let  x be the height in meters of the Statue of Liberty.

According to question, required equation is

\frac{1}{6.2}=\frac{15}{x}

Cross multiply,

x=15\times 6.2

x=93

Therefore, the height of statue of liberty is 93 meters.

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Anwers are top to bottom:

1.   y − 2,000 = 2,000 + 320x − 2,000

2.  division property of equality

3.    Y - 2000/320 = X

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Step-by-step explanation:

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The area of a trapezoid is 144 square inches. if the height is 12 inches, find the length of the median.
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An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
alekssr [168]

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

4 0
2 years ago
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