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PilotLPTM [1.2K]
2 years ago
6

In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and

0.91, respectively. Suppose that three bits are transmitted and that the amount of distortion of each bit is assumed to be independent. Let and denote the number of bits with high and moderate distortion out of the three, respectively. Determine the following:
A. fxy(x,y).
B. fx(x).
C. E(X).
D. Are X and Y independent?

Mathematics
1 answer:
Leviafan [203]2 years ago
7 0

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

<h3 /><h3>STEP 1:</h3>

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

<h3>STEP 2:</h3>

A.

The function will follow multinomial distribution:

f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})

Substitute the values and make a table.

TABLE IN ATTACHMENT

<h3>STEP 3:</h3>

B.

We calculate marginal distribution by:

P (X=x)= <em>∑</em> P(X=x,Y=y)

fx(x) can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

<h3>STEP 4:</h3><h3>C.</h3>

The mathematic expectation E is the sum of product of each possibility with its probabiity.

E(X)=<em>∑ </em>xP(X=x)

Find E(X):

E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)

E(X)=0.06

<h3>STEP 5:</h3>

Condition probability states:

P(A|B)=\frac{P(A,B)}{P(B)}

It can also be written as:

f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}

Where f_x(1)\\ = 0.057624

Calculate the quotient:

Y|_{x=1} = 0 ,  f_{Y|_X=1 = 0.862245

Y|_{x=1} = 1 ,  f_{Y|_X=1 = 0.132653

Y|_{x=1} = 2 ,  f_{Y|_X=1 = 0.000510

Y|_{x=1} = 3 ,  f_{Y|_X=1 = 0

Find the dependency:

f_{XY}(y)=f_X(x)f_Y(y)

We found that

f_{Y|_X=1 = 0.862245

Calculate f_Y(1) from summing the column from the table

f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141

Which are not equal.

Conclusion:

X and Y are NOT Independent

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B. ⅕

Step-by-step explanation:

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The owner of a candy store wants to mix some peanuts worth $3 per pound, some cashews worth $10 per pound, and some Brazil nuts
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Let
x = pounds of peanuts
y = pounds of cashews
z = pounds of Brazil nuts.

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x + y + z = 50                   (1)

The total cost is $6.60 per pound for 50 pounds of mixture.
The total is equal to the sum of the costs of the different nuts.
Because the cost for peanuts, cashews, and Brazil nuts are $3, $10, and $9 respectively, therefore
3x + 10y + 9z = 50*6.8
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There are 10 fewer pounds of cashews than peanuts, therefore
x = y + 10                         (3)

Substitute (3) into (1) and (2).
y + 10 + y + z = 50
2y + z = 40                     (4)
3(y + 10) + 10y + 9z = 340
13y + 9z = 310                (5)

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z = 40 - 2y          (6)
Substitute (6) into (5).
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The ratio of boys to girls in a certain classroom was 2 : 3. If boys represented five more than one third of the class, how many
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Let the no. Of boys=x and that of girls=y.
The total no. Of students = x+y .
As given by statement the no. Of boys=x={(x+y)/3} + 5
This implies that
X=(x+y+15)/3
Also we know that x/y = 2/3 therefore
From this equation we get x=2y/3 and y=3x/2
By method of substitution we get
X=(x+3x/2+15)/3
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Step-by-step explanation:

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Sample size, n = 100

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Alpha, α = 0.01

Sample standard deviation, s = $25

First, we design the null and the alternate hypothesis

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We use two-tailed t test to perform this hypothesis.

Formula:

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