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Nat2105 [25]
2 years ago
13

At an intersection, the red-light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25

minutes. Using the empirical rule, approximately what percent of red lights last between 2.5 and 3.5 minutes?

Mathematics
1 answer:
denpristay [2]2 years ago
3 0

Percent of red lights last between 2.5 and 3.5 minutes is 95.44% .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that 2.5<X<3.5 is equal to the blue area under the curve.

Step 2:

Since μ=3 and σ=0.25 we have:

P ( 2.5 < X < 3.5 ) =P ( 2.5−3 <  X−μ < 3.5−3 )

⇒ P ( (2.5−3)/0.25 < (X−μ)/σ < (3.5−3)/0.25)

Since, Z = (x−μ)/σ , (2.5−3)/0.25 = −2 and (3.5−3)/0.25 = 2 we have:

P ( 2.5<X<3.5 )=P ( −2<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( −2<Z<2 )=0.9544

Percent of red lights last between 2.5 and 3.5 minutes is 0.9544(100) = 95.44% .

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The shoe store manager borrowed $17,000.00 from the bank to purchase 1000 pairs of shoes. The bank charges a simple interest rat
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Answer:

2550

Step-by-step explanation:

1) So he borrowed 17,000

2) Simple interest is 5%

3) so 0.05 *17000 = 850

4)It takes the manager 3 years so, 850*3=2550

5) so 2550 is the total amount of interest the manager needs to pay

7 0
1 year ago
A local factory uses a manufacturing process in which 70% of the final products meet quality standards and 30% are found to be d
frosja888 [35]
<span>Answer:
   a manufacturing process has a 70% yield, meaning that 70% of the porducts are acceptable and 30% are defective. If three of the products are randomly selected, find the probability that all of them are acceptable. ---
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8 0
2 years ago
A combination washer/dryer costs $1,179. New parts for this washer/dryer cost $211, labor to repair it costs $553, and shipping
Keith_Richards [23]
The better deal is the Full Warranty, by approximately 174 dollars. To solve the cost of the full warranty, simply multiply 30 percent times the cost of the washer/dryer.30 x 1,179 = 353.70. You do not need to add anything to this because the warranty covers the extra costs. To solve for the cost of the limited warranty, multiply 14 percent times the cost of the washer/dryer, plus the cost of the new parts and the repair center costs (the warranty only covers the labor repair costs): (.14 x 1,179) + 211 + 152 --> 165.06 + 211 + 152 = 528.06. The full warranty is clearly cheaper. To figure out by how much, simply subtract the full warranty from the limited warranty: 528.06 - 353.70 = 174.36. To round to the nearest number, take off the decimal: 174. So that means your answer is D hope this helps.
3 0
2 years ago
Read 2 more answers
if I have 436 baseball cards and 189 football cards.how many more baseball cards than football cards do I need
Mashcka [7]
Hello,

Here is your answer:

The proper answer to this question is your going to need "247"

436-189=247

Which means your going to need 247 more baseball cards then football cards!

Your answer is 247.

If you need anymore help feel free to ask me!

Hope this helps!
5 0
2 years ago
Read 2 more answers
Tavon has a gift card for $165 that loses $4 for each 30-day period it is not used. He has another gift card for $145 that loses
sweet [91]

Answer:

Equation 1 = Equation 2

165 - 4x = 145 - 3.50x

Step-by-step explanation:

Let x represent the number of 30-day periods.

Tavon has a gift card for $165 that loses $4 for each 30-day period it is not used.

Therefore the equation =

$165 -$4 × x

= 165 - 4x.......... Equation 1

He has another gift card for $145 that loses $3.50 for each 30-day period it is not used.

$145 -$3.50 × x

= 145 - 3.50x........... Equation 2

Hence, an equation for the number of 30-day periods until the value of the gift cards will be equal is obtained by equating Equation 1 and Equation 2 together

So, we have

Equation 1 = Equation 2

165 - 4x = 145 - 3.50x

We simplify further:

165 - 145 = -3.50 + 4.0x

20 = 0.5x

x = 20/0.5

x = 40

Therefore, number of each 30-day periods until the value of the gift cards will be equal is 40

3 0
2 years ago
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