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Wittaler [7]
2 years ago
9

In a certain elementary school, 52% of the students are girls. A sample of 65 students is drawn. Would it be unusual for more th

an 70% of them to be girls? Clearly explain your reason. (Note that your random variable is the sample proportion).
Mathematics
1 answer:
aksik [14]2 years ago
4 0
P = 52% = 0.52
SE = sqrt(p(1 - p)/n) = sqrt(0.52(1 - 0.52)/65) = sqrt((0.52 x 0.48) / 65) = sqrt(0.00384) = 0.0620

Let x be a random variable representing the percent of girls in the sample, then
P(x > 0.70) = 1 - P(x < 0.70) = 1 - P(z < (0.70 - 0.52) / 0.0620) = 1 - P(z < 2.905) = 1 - 0.99816 = 0.00184

The probability that there will be more than 70% of girls in the sample is 0.00184. Therefore, it will be unusual for more than 70% of them to be girls.
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A bar graph titled Album Type Sold per Year has year on the x-axis and number of albums sold on the y-axis. For C D s, in 2008 t
stira [4]

Answer:

True, True, False, True, False, True

Step-by-step explanation:

<u>CDs have a higher mean than digital</u>

<u />

Let's check.  CD mean is (1000 + 800 + 800 + 600 + 400 + 200)/6 = 633.33

Digital mean: (100 + 300 + 300 + 500 + 700 + 900)/6 = 466.67

CD's mean is higher.  Since you are dividing byt he same number you also could have just added the amount and found which was a larger number.  But yes, this is true.

<u>The range of digital is 800</u>

<u />

The range is the highest number inus the lowest number.  For digital the highest is 900 and lowest is 100 so the ange is 900-100 = 800.  So this is true.

<u>The median of CDs is 400. </u>

<u />

The median is the middle value for odd numbers of values, or the average of the two middle values.  6 total values means you have to take the third and fourth and average them.  in CDs the middle values are 800 and 600, the average is 700, so that is what the median is.  this is false.

<u>Both have the same interquartile range. </u>

<u />

Interquartile range is to find the middle number or numbers like in median, then take the two parts it is split into and find the "median" of those.  Then subtract the larger one fromt he smaller one.

IQR of CD the first half is 200, 400, 600 so the middle here is 400, second half has a middle number of 800 so IQR here is 800-400=400

IQR of digital is 700-300 = 400 so yes both are the same.

<u>Both have the same median</u>

<u />

We know the medan of CDs is 700 then findign the median of digital is (300+500)/2 = 400.  So no, the medians are not the same.

<u>Digital’s mean is around 467. </u>

<u />

We founf the mean for digital to be 466.67 which rounds up to 467, So I would say it is true.

8 0
2 years ago
Read 2 more answers
Danica has laid out floor tiles so they form a rectangle with a perimeter of 18 inches.what is the differnce between the greates
9966 [12]
Technically you would have to divide 18 in half which is 9 so 9 is your possible answer.
5 0
2 years ago
Read 2 more answers
What is the recursive formula for this arithmetic sequence? -4, 3, 10, 17, ...
MatroZZZ [7]
<span>a1 = 3
an = a (n-1) +7</span>
5 0
2 years ago
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Mrs. aviles is planning a fruit-cup party for a class of 18 students and two teachers. She spends $10 for a package of snacks an
zzz [600]

Answer:

domain is x = 3

Thus domain means that for every fruit cup costs $3

Range is f(20) = 60

Step-by-step explanation:

We are given;

Total students for the fruit cup party = 18

Total teachers for the fruit cup party = 2

Cost of each fruit cup =$ 3

Delivery charge = $ 10

Now, the total number of people attending the party = Total number of students + Total number of teachers

Thus;

Total number of people attending party = 18 + 2 = 20

Since cost of each fruit cup is $3.

Thus, for 20 fruit cups, the function is;

f(x) = 20x where x is cost of each fruit cup.

It means the cost of 20 fruit cups = $3 × 20 = $60

Thus, domain is x = 3

Thus domain means that for every fruit cup costs $3

Range is f(20) = 60

6 0
1 year ago
QUESTION THREE (30 MARKS) 3.1 The mass of a standard loaf of white bread is, by law meant to be 700g with a population standard
kiruha [24]

Using the normal distribution and the central limit theorem, it is found that  there is a 0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

----------------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

----------------------------------

  • Mean of 700g means that \mu = 700
  • Standard deviation of 21g means that \sigma = 21
  • Sample of 64, thus n = 64
  • <u>For the sampling distribution of the sample mean</u>, the standard deviation is of s = \frac{21}{\sqrt{64}} = \frac{21}{8} = 2.625

The probability of finding a sample mean mass of 695g or below is the p-value of Z when X = 695, thus:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{695 - 700}{2.625}

Z = -1.905

Z = -1.905 has a p-value of 0.0284.

0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

A similar problem is given at brainly.com/question/22934264

7 0
2 years ago
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