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maria [59]
2 years ago
6

Sam and Edna have 56 marbles together Edna has 6 times more marbles than Sam. How many marbles does sam have ?

Mathematics
2 answers:
Elis [28]2 years ago
7 0
The answer is 8 marbles. 6*8=48. 48(ednas marbles) + 8(sam's marbles)=56.
nataly862011 [7]2 years ago
4 0

Answer:  Sam 25 marbles.

Step-by-step explanation:  Given that Sam and Edna have 56 marbles together and  Edna has 6 times more marbles than Sam.

We are to find the number of marbles that Sam has.

Let x and y represents the number of marbles that Sam and Edna has respectively.

Then, according to the given information, we have

x+y=56\\\\\Rightarrow y=56-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y=x+6\\\\\Rightarrow 56-x=x+6\\\\\Rightarrow 2x=50\\\\\Rightarrow x=\dfrac{50}{2}\\\\\Rightarrow x=25.

Thus, Sam has 25 marbles.

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Harry's soccer team is trying to raise $2520 to travel to a tournament in Florida, so they decided to host a pancake breakfast.
Serggg [28]

Answer: 168 people have to attend

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2 years ago
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
babunello [35]

For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • <em>g: acceleration of gravity </em>
  • <em>vo: initial speed </em>
  • <em>h0: initial height </em>

For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Clearing time:

t = 29 (\frac {12} {19})\\t = 18.31s

Answer:

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6 0
2 years ago
Read 2 more answers
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles
Ugo [173]

By definition, the average rate of change is given by:

AVR = \frac{f(x2)-f(x1)}{x2-x1}

We evaluate each of the functions in the given interval.

We have then:

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Evaluating for x = -2:

f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2

Evaluating for x = 3:

f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18

Then, the AVR is:

AVR = \frac{18-(-2)}{3-(-2)}

AVR = \frac{18+2}{3+2}

AVR = \frac{20}{5}

AVR = 4


For f (x) = 3x - 8:

Evaluating for x =4:

f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4

Evaluating for x = 5:

f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7

Then, the AVR is:

AVR = \frac{7-4}{5-4}

AVR = \frac{3}{1}

AVR = 3


For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15

Evaluating for x = 4:

f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8

Then, the AVR is:

AVR = \frac{8-15}{4-(-3)}

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AVR = \frac{-7}{7}

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For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4

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f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4

Then, the AVR is:

AVR = \frac{-4-(-4)}{1-(-1)}

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Answer:

from the greatest to the least value based on the average rate of change in the specified interval:


f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]


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2 years ago
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musickatia [10]

Answer:

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Step-by-step explanation:

55/100 converted to ?/180

180/100=1.8

so you would do the same on the numerator which is 55*1.8=99

99/180= 33/60=11/20

7 0
2 years ago
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