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mixer [17]
1 year ago
12

In a high school there are 1200 students. Estimate the probability that more than 130 students were born in January under each o

f the following assumptions. You do not have to use the continuity correction.
(a) Months are equally likely to contain birthdays
(b) Days are equally likely to be birthdays
Mathematics
1 answer:
ziro4ka [17]1 year ago
3 0

Answer:

The probability that more than 130 students were born in January under the given assumptions is 0.00086

Step-by-step explanation:

Let X be a variable denoting the number of birthdays in January.

P(that a gien birthday is in the month of January)    =   \frac{1}{12}

                                                                 E(X) = np = 1200\times\frac{1}{12} = 100                                                                                                                                                                                          

                                                                   σ = \sqrt{ (np ( 1 -p ))} = 9.5743

Now, as per question

P (X> 130) = 1 - P( x ≤ 130)

                 = 1 - P (Z ≤  \frac{130 - 100}{9.53742} )

                  = 1 - 0.99914

                  =0.00086

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You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.

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You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.

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5 0
2 years ago
15 Points!
goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC =\frac{b}{a-c}

Step-by-step explanation:

According to midpoint formula

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

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x=\frac{x_{1} +x_{2} }{2} and y=\frac{y_{1} +y_{2} }{2}

now from the given diagram A is the mid point of line joining  R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

x=\frac{0+2a}{2}= a and y=\frac{0+2b}{2} =b

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

x= \frac{2c+2c}{2} =2c and y=\frac{2d+0}{2} =d

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the slope of PQ =\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

hence slope of AD= \frac{0-b }{c-a}

                                 =\frac{-b}{c-a}

                                  =\frac{-b}{-(a-c)}

                                  =\frac{b}{a-c}

and slope of BC  =\frac{d-(b+d)}{2c-(a+c)}

                            =\frac{d-b-d}{2c-a-c}

                             =\frac{-b}{c-a}

                              =\frac{b}{a-c}

so we have

slope of AD and BC =\frac{b}{a-c}

7 0
2 years ago
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Andrea conducts a science experiment and observes that the height of a plant depends on the amount of sunlight it receives. The
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Answer:

Option C. F(s)=0.004s+37

Step-by-step explanation:

Let

F(s) ----> the plant's height in cm

s -----> the number of hours of sunlight

we know that

The equation of the line in slope intercept form is equal to

y=mx+b

where

m is the slope of rate of change

b is the y-intercept or initial value

In this problem we have

m=0.004 cm/h -----> the slope is the rate of grow

b=37 cm ----> the y-intercept (initial value)

substitute the values in the equation

y=0.004s+37

Convert to function notation

F(s)=0.004s+37

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2 years ago
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Our math team had m students last year, but this year it has already n students! By what percent did the number of students grow
Musya8 [376]

Answer:

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2 years ago
A random sample of 1800 NAU students in Flagstaff found 1134 NAU students who love their MAT114 class. Find a 95% confidence int
seropon [69]

Answer:

95% confidence interval for the true percent of NAU students in Flagstaff who love their MAT114 class is (60.77% , 65.23%)

Step-by-step explanation:

Among 1800 NAU students, 1134 students love their class. We have to find the 95% confidence interval of students who love their class.

We will use the concept of confidence interval of population proportion for this problem.

The proportion of students who love the class = p = \frac{1134}{1800}=0.63

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Confidence Level = 95%

The z values associated with this confidence level(as seen from z table) = 1.96

The formula to calculate the confidence interval for population proportion is:

(p-z\times\sqrt{\frac{p \times q}{n}},p+z\times\sqrt{\frac{p \times q}{n}})

Using the values in this expression gives:

(0.63-1.96 \times \sqrt{\frac{0.63 \times 0.37}{1800}}, 0.63+1.96 \times \sqrt{\frac{0.63 \times 0.37}{1800}})\\\\ =(0.6077,0.6523)

Thus, 95% confidence interval for the true percent of NAU students in Flagstaff who love their MAT114 class is (0.6077 ,0.6523) or (60.77% , 65.23%

6 0
1 year ago
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