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mixer [17]
2 years ago
12

In a high school there are 1200 students. Estimate the probability that more than 130 students were born in January under each o

f the following assumptions. You do not have to use the continuity correction.
(a) Months are equally likely to contain birthdays
(b) Days are equally likely to be birthdays
Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

Answer:

The probability that more than 130 students were born in January under the given assumptions is 0.00086

Step-by-step explanation:

Let X be a variable denoting the number of birthdays in January.

P(that a gien birthday is in the month of January)    =   \frac{1}{12}

                                                                 E(X) = np = 1200\times\frac{1}{12} = 100                                                                                                                                                                                          

                                                                   σ = \sqrt{ (np ( 1 -p ))} = 9.5743

Now, as per question

P (X> 130) = 1 - P( x ≤ 130)

                 = 1 - P (Z ≤  \frac{130 - 100}{9.53742} )

                  = 1 - 0.99914

                  =0.00086

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Alex73 [517]

Answer:

The inverse function is y=\sqrt{\frac{x+4}{2}}


Step-by-step explanation:

The given function is y=2x^2-4.


This function is only invertible on the interval, x\ge 0.


To find the inverse on this interval, we interchange x and y.

x=2y^2-4


We now make y the subject to get,


x+4=2y^2


\Rightarrow \frac{x+4}{2}=y^2


\Rightarrow \pm \sqrt{\frac{x+4}{2}}=y


But the given interval is x\geq 0, This implies that, y\geq 0.


y=\sqrt{\frac{x+4}{2}}


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2 years ago
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Step-by-step explanation:

We have,

Height of cone, h = 12.7 m

Circumference of base, C = 18.9 m

The base of a circular cone is circular. The circumference of circle is given by :

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The volume of a right circular cone is given by the formula as :

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V=\dfrac{1}{3}\times 3.14 \times 3^2\times 12.7\\\\V=119.634\ m^3

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It is common in many industrial areas to use a filling machine to fill boxes full of product. This occurs in the food industry a
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Answer:

(a) P(B) = 0.008, (b) P(A∩B) = 0, (c) Yes, A and B are mutually exclusive events, (d) P(A∪B)=0.948, (e) 0.948, (f) 0.06

Step-by-step explanation:

We have three different posibilities

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in probability the sum of the different events which are mutually exclusive should sum to 1, so, we should have

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P(A∪B)=P(A)+P(B)=0.940+0.008=0.948

(e) The probability that the machine does not overfill is the same that the probability that the machine fill to specification plus the probability that the machine underfill, i.e, the probability that the machine does not overfill is P(A)+P(B)=0.948, because does not overfill is equivalent either to fill to specification or to underfill.

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Step-by-step explanation:

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Answer:

Option A , should not be rejected

Step-by-step explanation:

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Sample 2 n=16

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Generally The Hypothesis are given as

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From Table

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