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hram777 [196]
1 year ago
11

Triangle PQR with vertices P(3, −6), Q(6, −9), and R(−15, 3) is dilated by a scale factor of 3 to obtain triangle P′Q′R′. Which

statement best describes triangle P′Q′R′?A. It is similar to triangle PQR and has coordinates P′(1, −2), Q′(2, −3), and R′(−5, 1).B. It is congruent to triangle PQR and has coordinates P′(1, −2), Q′(2, −3), and R′(−5, 1).C. It is similar to triangle PQR and has coordinates P′(9, −18), Q′(18, −27), and R′(−45, 9).D. It is congruent to triangle PQR and has coordinates P′(9, −18), Q′(18, −27), and R′(−45, 9).
Mathematics
1 answer:
vovangra [49]1 year ago
6 0

Answer:

Option C.

Step-by-step explanation:

The vertices of triangle PQR are P(3, −6), Q(6, −9), and R(−15, 3).

It is given that triangle PQR dilated by a scale factor of 3 to obtain triangle P′Q′R′.

We know that a figure and its image after dilation are similar. It means triangle PQR and triangle P′Q′R′

If a figure dilated by factor k about the origin then

(x,y)\rightarrow (kx,ky)

PQR dilated by a scale factor of 3, so

(x,y)\rightarrow (3x,3y)

Using this rule we get

P(3,-6)\rightarrow P'(3(3),3(-6))=P'(9,-18)

Q(6,-9)\rightarrow Q'(3(6),3(-9))=Q'(18,-27)

R(-15,3)\rightarrow R'(3(-15),3(3))=R'(-45,9)

The vertices of image are P'(9,-18), Q'(18,-27) and R'(-45,9).

Therefore, the correct option is C.

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The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is .
Readme [11.4K]

Answer:

(-21,-19)

\sqrt{849}

Standard form

Step-by-step explanation:

We are given the equation of circle

x^2+y^2+42x+38y-47=0

General equation of circle:

x^2+y^2+2gx+2fy+c=0

Centre: (-g,-f)

Radius: \sqrt{g^2+f^2-c}

Compare the equation to find f, g and c from the equation

g\rightarrow 21

f\rightarrow 19

c\rightarrow -47

Centre: (-21,-19)

Radius (r) =\sqrt{21^2+19^2+47}=\sqrt{849}

Standard form of circle:

(x+21)^2+(y+19)^2=849

The centre of circle at the point (-21,-19) and its radius is \sqrt{849}.

The general form of the equation of a circle that has the same radius as the above circle is standard form.

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2 years ago
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The mean score of a competency test is 82, with a standard deviation of 2. Between what two values do about 99.7% of the values
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99.7% encompasses about 3 standard deviations either side of the mean.

82 ±3*2 = (76, 88)

About 99.7% of the values lie between 76 and 88.
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1 year ago
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Which graph represents the function of f(x) = the quantity of 9 x squared plus 9 x minus 18, all over 3 x plus 6
lora16 [44]

Answer:

The answer is the option C

graph of 3x minus 3, with discontinuity at negative 2, negative 9

Step-by-step explanation:

we have

f(x)=\frac{9x^{2}+9x-18}{3x+6}

Simplify

f(x)=9\frac{(x^{2}+x-2)}{3(x+2)}

f(x)=3\frac{(x^{2}+x-2)}{(x+2)}

Step 1

Convert to a factored form the numerator

x^{2}+x-2=0    

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+x=2

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+x+0.25=2+0.25

x^{2}+x+0.25=2.25

Rewrite as perfect squares

(x+0.5)^{2}=2.25

Square root both sides

x+0.5=(+/-)1.5

x=-0.5(+/-)1.5

x=-0.5+1.5=1

x=-0.5-1.5=-2

so

x^{2}+x-2=(x-1)(x+2)  

Step 2

Simplify the function f(x)

f(x)=3\frac{(x^{2}+x-2)}{(x+2)}=3\frac{(x-1)(x+2)}{(x+2)}

The domain of the function f(x) is all real numbers except the number x=-2

Because the denominator can not be zero

f(x)=3\frac{(x-1)(x+2)}{(x+2)}=3(x-1)=3x-3  

f(x)=3x-3  ------> with a discontinuity at x=-2

f(-2)=3(-2)-3=-9

The discontinuity is at point (-2,-9)

the answer in the attached figure

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Butoxors [25]
Answer:
Interest earned = 2713.8

Explanation:
We will solve this problem on two steps:
1- get the final amount after three years
2- get the interest earned by subtracting the initial amount from the final one.

1- getting the final amount after 3 years:
The formula that we will use is as follows:
A = P (1 + r/n)^(nt)
where:
A is the final amount we want to calculate
P is the initial amount = 6300
r is the interest = 0.12
n is the number of compounds per year =12
t is time in years = 3

Substitute to get the final amount:
A = P (1 + r/n)^(nt)
A = 6300 (1 + 0.12/12) ^ (12*3)
A = 9013.8

2- getting the interest earned:
Interest earned = final amount - initial amount
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Interest earned = 2713.8

Hope this helps :)
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