All categories

2 years ago

Which expression can be used to find the sum of the polynomials? (9 – 3x2) (–8x2 4x 5)

Mathematics

2 answers:

SIZIF [17.4K]2 years ago

7 0

For this case we have:

Polynomial 1: $P (x) = 9-3x ^ 2$

Polynomial 2: $Q (x) = - 8x ^ 2 + 4x + 5$

Sorting the polynomials:

Polynomial 1: $P (x) = - 3x ^ 2 + 9$

Polynomial 2: $Q (x) = - 8x ^ 2 + 4x + 5$

Adding term to term (similar) we have:

$P (x) + Q (x) = (- 3-8) x ^ 2 + (0 + 4) x + (9 + 5)\\P (x) + Q (x) = - 11x ^ 2 + 4x + 14$

Answer:

$A (x) = P (x) + Q (x) = - 11x ^ 2 + 4x + 14$

GarryVolchara [31]2 years ago

7 0

It seems that you missed the choices of the given question above.
Anyway, here is the correct answer of the given polynomial above. The answer is [(-3x^2)+(-8x^2)]+4x+[9+5]. The expression that can be used to find the sum of the polynomials given above is [(-3x^2)+(-8x^2)]+4x+[9+5].

You might be interested in

The perimeter of a square is represented by the expression 32x - 12.8. Draw a square to represent this situation and label its s

Hoochie [10]

Answer:

Step-by-step explanation:

Given that: The perimeter of a square is: 32x - 12.8

As we all know that, the formula to find the perimeter of a square is:

Sum of the 4 side = 4* length of the side

=> the length of 1 side: The perimeter of a square / 4

In this situation, we have length of 1 side side is:

(32x - 12.8) / 4

= 32/4x - 12.8/4

= 8x - 3.2

The 1st equivalent expressions for the perimeter: 4 *(8x - 3.2)

The 2nd equivalent expressions for the perimeter: (8x - 3.2) + (8x - 3.2) + (8x - 3.2) + (8x - 3.2)

The 3rd equivalent expressions for the perimeter: 2*(8x - 3.2) + 2*(8x - 3.2)

3 0

1 year ago

1. Ernie Boddy had $3,620.00 on deposit at savings bank on July 1. The money earns interest at a rate of 6.5% compounded quarter

laila [671]

Answer:

235.3$ for part a

7 0

1 year ago

Christian is rewriting an expression of the form y = ax2 + bx + c in the form y = a(x – h)2 + k. Which of the following must be

Shkiper50 [21]

Answer:

The Value Remains the Same

Step-by-step explanation:

Trust

7 0

1 year ago

Read 2 more answers

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

1 year ago

It shipped traveled for a total of 85 miles over the course of five hours heading west the ship travels and average of 14 mph an

adoni [48]

complete question:

A ship traveled for a total of 85 miles over the course of 5 hours. Heading west, the ship traveled at an average speed of 14 miles per hour, and heading north, it traveled at an average speed of 19 miles per hour. For how many hours was the ship heading north?

Answer:

The ship heading north traveled for 3 hours

Step-by-step explanation:

A ship travels for a total of 85 miles over the course of 5 hours journey. The speed of the journey can be calculated below.

speed = distance/time

total distance = 85

total time = 5 hours

speed = 85/5

speed = 17 miles/hr

West direction

Heading west the ship traveled at an average speed of 14 miles per hour. The speed can be represented for this journey as follows.

speed = distance/time

14 = dist/time

let

a = time traveled west

distance = 14a

North direction

speed = dist/time

19 = dist/time

time travel north = 5 - a

distance = 19(5 - a)

distance = 95 - 19a

Total distance traveled = 85 miles

85 = 14a + 95 - 19a

85 = -5a + 95

-10 = -5a

a = -10/-5

a = 2

The ship heading north will travel for 5 - 2 = 3 hours

5 0

2 years ago

Read 2 more answers