Question

Solve for q. 22q+73 > 52q + 63

Answer 1

Hey!

Let's write the problem.
$22q+73\ \textgreater \ 52q+63$
Subtract $73$ from both sides.
$22q+73-73\ \textgreater \ 52q+63-73$
$22q\ \textgreater \ 52q-10$
Subtract $52q$ from both sides.
$22q-52q\ \textgreater \ 52q-10-52q$
$-30q\ \textgreater \ -10$
Since we don't want negative, we will multiply both sides by $-1$.
$\left(-30q\right)\left(-1\right)\ \textless \ \left(-10\right)\left(-1\right)$
$30q\ \textless \ 10$
Divide both sides by $30$.
$\frac{30q}{30}\ \textless \ \frac{10}{30}$

Our final answer would be,
$q\ \textless \ \frac{1}{3}$

Thanks!
-TetraFish