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alexandr402 [8]
1 year ago
13

Graduation is 3 years away and you want to have $750 available for a trip. If your bank is offering a 3-year CD (certificate of

deposit) paying 2.2% simple interest, how much do you need to put in this CD to have the money for your trip?
Mathematics
1 answer:
nlexa [21]1 year ago
6 0

Answer:

you will put 2.2% interest which represents your C D, by then they will add 750+2.2

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If one serving is 1/6 of a tray of lasagna, how many servings are in three trays of lasagna?
lbvjy [14]

Answer:

18 servings

Step-by-step explanation:

\dfrac{3}{(\frac{1}{6})}= \\\\3\times \left(\frac{6}{1}\right)= \\\\3\times 6= \\\\18

Hope this helps!

4 0
1 year ago
A-B=18 A:B is equivalent to 11:5
densk [106]
One way is to use brute force (find bigger equivalent ratios and add them)
11:5
to make them bigger, we multiply both by the same number 
11:5
11+5=16 nope
11:5 times 5 to both=55:25
add 
55+25=80
we can just add the numbers before multiplying and then multiply after

11+5=16
16 times what=18
divide both sides by 16
1.125=what
we need to multiply each by 1.125
11:5 times 1.125 to both =12.375 : 5.625
12.375+5.625=18

a=12.375
b=5.625

Hope this helps :)
8 0
1 year ago
Read 2 more answers
R(-9, 4) and S(2,-1); Find T.
madreJ [45]

Answer:

12.083 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-9,4)

(x_2,y_2) = (2,-1)

Replacing these values in the distance formula

D =\sqrt{(-9-2))^2+(4-(-1))^2}

D =\sqrt{(-11)^2+(5)^2}

D =\sqrt{121+25}

D =\sqrt{146}

D= 12.083

Hence the distance is 12.083 units

3 0
1 year ago
You use index cards to play a homemade game. The object is to be the first to get rid on all your cards. How many cards are in y
pav-90 [236]
 the number of cards in my friends stack is  20 total cards

3 0
1 year ago
Read 2 more answers
Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)
andrezito [222]

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = ln(x^4 + 27)

f'(x) = 1/(x^2 + 27)

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 1/(x^2 + 27)

0 = 1/(x^2 + 27)

Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.

6 0
2 years ago
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