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Blababa [14]
2 years ago
8

Lori ran the distances shown in the table. write the total distance in miles as a fraction in simplest form

Mathematics
1 answer:
daser333 [38]2 years ago
8 0
0.35+0.2+.25
=0.55+0.2
=0.57
=57/100 miles
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Factorise 125x^3 -27y^3
telo118 [61]

Answer:

(5x - 3y)(25x² +15xy + 9y²)

Step-by-step explanation:

125x³ - 27y³ is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

Given

125x³ - 27y³

= (5x)³ - (3y)³

= (5x - 3y)((5x)² + (5x)(3y) + (3y)²)

= (5x - 3y)(25x² + 15xy + 9y²)

6 0
2 years ago
I am paying $60.00 a month for my service. I would like to upgrade to the $80.00 service package because my new employer offers
Irina18 [472]

Answer:

that would be 16 dollars

Step-by-step explanation:

80.00 multiplied by .2 equals 16

8 0
2 years ago
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Ben sells greeting cards for $5 each in his online store. He also charges $1.99 for shipping. The total cost, y, of an order fro
laila [671]
5 would be the dependent variable because the number 5 depends on how many greeting cards are bought.
7 0
2 years ago
Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of
bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

                                                                                                        =\frac{7}{100}

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = 1-\frac{7}{100}

                  ⇒ prob = \frac{93}{100}

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = (\frac{93}{100})^{12}

Therefore, Probability of atleast one of 12 student has food allergies

                  = 1-(\frac{93}{100})^{12}

                  = 0.581403702521

                  ≈ 0.58 ( approx)

                 

8 0
2 years ago
Read 2 more answers
Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10
Iteru [2.4K]

Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

where B_0 is the initial number of bacteria.  

Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

8 0
2 years ago
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