Hi there
The formula of compound interest is
A=p (1+r/k)^kn
A future value?
P present value 12300
R interest rate 0.052
K compounded quarterly 4
N time 1 year
So
A=12,300×(1+0.052÷4)^(4×1)
A=12,952.18
Good luck!
We have been given that Bobby's investment of $225,000 loses value at a rate of 3% per year. We are asked to find the value of the investment after 10 years.
We will us exponential decay function to solve our given problem.
We know that an exponential function is in form 
, where,
y = Final amount,
a = Initial amount,
r = Decay rate in decimal form,
x = Time.
Let us convert 3% into decimal.
Upon substituting 
, 
and 
, we will get:
Upon rounding to nearest dollar, we will get;
Therefore, the value of the investment after 10 years would be 
.
Answer:
w = y - x is the equation to find w
Where,
w = Weight of the liquid
x = Weight of the empty can
y = Weight of the can with liquid
Step-by-step explanation:
Let
Weight of the empty can = x
Weight of the liquid = w
Weight of the can with liquid = x + w = y
x= 30 grams
w = ?
y= 47.3 grams
y = x + w
w = y - x
= 47.3 - 30
= 17.3
w= 17.3 grams
Therefore, the weight of the liquid is 17 .3 grams
We are given the equation:
<span>Z(q) = 4q + ½ --->
1</span>
The equation for z(u + 1/2) is obtained by
substituting q with u + ½ in the equation, therefore we can say that:
<span>q = u + ½ --->
2</span>
Substituting this value into equation # 1:
Z = 4 (u + ½) + ½ = z (u + 1/2)
4 u + 2 + ½ = z (u + 1/2)
<span>Since it was given that z (u +
1/2) = ½ then,</span>
4 u + 2 + ½ = ½
4 u + 2.5 = 0.5
4 u = -2
u = -1/2 (ANSWER)
<span> </span>
