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Ierofanga [76]
2 years ago
10

Jason Aldeen bought a house for $275,000. He made a down payment of 15%. The interest rate is 4.2% for 15 years.

Mathematics
1 answer:
Tpy6a [65]2 years ago
3 0

Answer:

Step-by-step explanation:

Jason's down payment= $41250

Amount he needs to borrow is

275000-41250 = $233750

Jason's monthly payment would be

248476.25/180 = $1380.42

The original cost of the house that Jason Aldeen bought is $275,000. He made a down payment of 15%. This means he paid 15% of the original cost of the house. Therefore,

Jason's down payment is 15% of $275000

= 15/100 × 275000 =0.15×275000

=$41250

Since Jason's down payment is smaller than the original cost of the house, he would need to borrow.

Amount he needs to borrow is

275000-41250 = $233750

If Jason borrows $233750 at a rate of 4.2% for 15 years

Total interest on $233750 for 15 years will be

= (233750×4.2×15) /100

= 14726250/100 = $14726.25

Total amount to be paid for 15 years will be amount borrowed + interest

=233750 + 14726.25 = $248476.25

Converting 15 years to months,

15 × 12 months = 180 months.

Jason's monthly payment would be

248476.25/180 = $1380.42

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What is the finance charge on $13,300 financed at 7.9 percent for 4 years if the monthly payment per $100 is $2.44?
luda_lava [24]

If you borrowed $100, then your monthly payment is $2.44

If you borrowed $200, then your monthly payment is 2*2.44 = 4.88

etc etc

We can set up a proportion

2.44/100 = x/13300

to figure out the monthly payment x. Cross multiply and solve for x

2.44*13300 = 100*x

100x = 2.44*13300

100x = 32452

x = 32452/100

x = 324.52

So the monthly payment is $324.52

An alternative way to get this monthly payment is to apply 2.44% to 13300, which is another way to view the phrase  "monthly payment per $100 is 2.44"

------------------

There are 48 months in 4 years (start with 12 mon = 1 yr, then multiply both sides by 4) so we multiply 48 by the monthly payment to get the result 48*324.52 = 15,576.96. This is the total amount you have to pay back which is the principal plus interest.

Subtract off the principal (amount borrowed) to find the interest or finance charge: 15,576.96 - 13,300 = 2,276.96

Answer: Choice B

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Answer:

You can use a calculator for the decimal operations, but practice some by hand because on the quiz and the test you will not have a calculator.

Step-by-step explanation:

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n winter, the price of apples suddenly went up by \$0.75$0.75dollar sign, 0, point, 75 per pound. Sam bought 333 pounds of apple
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$1.21 is the original price per pound...i too am having trouble with figuring out how to setup the equation!!
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Matthew ran 3/8 mile and then walked 7/10 mile. Which pair of fractions can he use to find how far he went in all? (A 15/40 and
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Before we could add these numbers, 3/8 and 7/10 need a common denominator. Both 8 and 10 go into 40.

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2 years ago
Read 2 more answers
Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

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