<h2>Answer</h2>
Cost of lectures = $7.33 per hour
<h2>Explanation</h2>
Let 
the cost of the exam hours
Let 
be the cost of the workshop hours
Let 
be the cost of the lecture hours.
We know from our problem that exam hours cost twice as much as workshop, so:
equation (1)
We also know that workshop hours cost twice as much as lecture hours, so:
equation (2)
Finally, we also know that 3hr exams 24hr workshops and 12hr lectures cost $528, so:
equation (1)
Now, lets find the value of :
Step 1. Solve for in equation (3)
equation (4)
Step 2. Replace equation (1) in equation (4) and simplify
equation (5)
Step 3. Replace equation (2) in equation (5) and solve for
Cost of lectures = $7.33 per hour
Answer:
BC:BN=8:3
Step-by-step explanation:
ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.
Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD
But, BC= BN+NC
Therefore, BC:BN=(BN+NC):BN
⇒BC:BN=(3+5):3
⇒BC:BN=8:3
Answer:
D. D: 0 ≤ b ≤ 10; R: 0 ≤ W(b) ≤ 120
Step-by-step explanation:
The problem statement tells you Owen can build up to 10 birdhouses, and that b represents that number. Then 0 ≤ b ≤ 10 is the domain described by the problem statement.
It also tells you that W(b) = 12b, so filling in values from 0 to 10 gives a range from 0 to 120: 0 ≤ W(b) ≤ 120.
These observations match choice D.
The four options are attached below
<u><em>Answer:</em></u>Second attachment is the correct choice
<u><em>Explanation:</em></u>ASA (angle-side-angle) means that two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle
<u>Now, let's check the choices:</u><u>First attachment:</u>
It shows that two sides and the included angle between them in the first triangle is congruent to the corresponding two sides and the included angle between them in the second one. This is congruency by SAS. Therefore, this option is
incorrect<u>Second attachment:</u>
It shows that two angles and the included side between them in the first triangle is congruent to the corresponding two sides and the included angle between them in the second triangle. This is congruency by ASA. Therefore, this option is
correct<u>Third attachment:</u>
It shows that the three angles in the first triangle are congruent to the corresponding three angles in the second one. This is not enough to prove congruency. Therefore, this option is
incorrect<u>Fourth attachment:</u>
It shows that the three sides in the first triangle are congruent to the corresponding three sides in the second one. This is congruency by SSS. Therefore, this option is
incorrect.
Based on the above, the second attachment is the only correct one
Hope this helps :)
The area of a rectangle is A = L * W. We have the area as 323 and the length as 17. Filling in our formula for area then, 323 = 17W. Divide both sides by 17 to solve for the width. W = 19
