The function expressed in the graph has a steeper slope than the function in the table.
and
The y-intercept is the same for both functions.
I just completed this assignment for edge.
The solution would be like
this for this specific problem:
Since the number of
charter schools is eight less than twice the number of alternative schools,
then it’s:
<span>2x - 8 </span><span>
<span>and then
<span>2x - 8 = 36 </span>
<span>2x = 44 </span>
x = 22 </span></span>
So
there are 22 Alternative Schools in
the county. I am hoping that this answer has satisfied your query
and it will be able to help you in your endeavor, and if you would like, feel
free to ask another question.
Answer:
![E[R]](https://tex.z-dn.net/?f=E%5BR%5D)
= 99 Ω
= 2.3094 Ω
P(98<R<102) = 0.5696
Step-by-step explanation:
The mean resistance is the average of edge values of interval.
Hence,
The mean resistance, ![E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}](https://tex.z-dn.net/?f=E%5BR%5D%20%3D%20%5Cfrac%7Ba%2Bb%7D%7B2%7D%20%20%3D%20%5Cfrac%7B95%2B103%7D%7B2%7D%20%3D%20%5Cfrac%7B198%7D%7B2%7D)
= 99 Ω
To find the standard deviation of resistance, we need to find variance first.
Hence,
The standard deviation of resistance, 
= 2.3094 Ω
To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.
From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696
It isn’t possible for them to have the same amount of horses. Let me explain.
If we wanted to distribute 21 horses between the 4 of them we would have to do 21/4. This equals 5.25, and we know that they aren’t going to bring 5 horses and .25 of a horse; that’s wack!
One person would have to have 6 horses instead of 5. This is probably the answer your teacher wants.
If they really wanted it to be even they could sell the extra horse. Then they could have 20/4=5.
Or they could share that extra horse and send it from place to place.
Hope this helps you!
