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tino4ka555 [31]
2 years ago
9

Two fathers and two sons own 21 horses. They are moving to different parts of the country and want to divide the horses evenly a

mong themselves. How is this possible?
Mathematics
1 answer:
ozzi2 years ago
7 0
It isn’t possible for them to have the same amount of horses. Let me explain.

If we wanted to distribute 21 horses between the 4 of them we would have to do 21/4. This equals 5.25, and we know that they aren’t going to bring 5 horses and .25 of a horse; that’s wack!

One person would have to have 6 horses instead of 5. This is probably the answer your teacher wants.

If they really wanted it to be even they could sell the extra horse. Then they could have 20/4=5.

Or they could share that extra horse and send it from place to place.

Hope this helps you!
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A whole number from 1 to 15 inclusive is picked at random.
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<u></u>

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Explanation:

The figure attached shows the <em>Venn diagram </em>for the given sets.

<em />

<em><u>a) What is the probability that the number chosen is a multiple of 3 given that it is a factor of 24?</u></em>

<em />

From the whole numbers 1 to 15, the multiples of 3 that are factors of 24 are in the intersection of the two sets: 3, 6, and 12.

There are a total of 7 multiples of 24, from 1 to 15.

Then, there are 3 multiples of 3 out of 7 factors of 24, and the probability that the number chosen is a multiple of 3 given that is a factor of 24 is:

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<em><u /></em>

<em><u>b) What is the probability that the number chosen is a factor of 24 given that it is a multiple of 3?</u></em>

The factors of 24 that are multiples of 3 are, again, 3, 6, and 12. Thus, 3 numbers.

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8 0
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