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tino4ka555 [31]
2 years ago
9

Two fathers and two sons own 21 horses. They are moving to different parts of the country and want to divide the horses evenly a

mong themselves. How is this possible?
Mathematics
1 answer:
ozzi2 years ago
7 0
It isn’t possible for them to have the same amount of horses. Let me explain.

If we wanted to distribute 21 horses between the 4 of them we would have to do 21/4. This equals 5.25, and we know that they aren’t going to bring 5 horses and .25 of a horse; that’s wack!

One person would have to have 6 horses instead of 5. This is probably the answer your teacher wants.

If they really wanted it to be even they could sell the extra horse. Then they could have 20/4=5.

Or they could share that extra horse and send it from place to place.

Hope this helps you!
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Answer:

f(x) = 500(2)^x

Step-by-step explanation:

Let's assume the initial x value is 0

500(0)^2 = 0

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500(2)^0 = 500

500(0)^2 = 0

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In the equation "y=m+b," what does the "m" stand for​
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There are two approaches to solving the equation -3x + 10 = 4x - 20 Subtract 4x from both sides. OR Add 3x to both sides. –7x +
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<u>Answer:</u>

There are two approaches to solving the equation -3x + 10 = 4x - 20. The value of x after solving in both methods is 4.2857.

<u>Solution:</u>

Given, equation is -3x + 10 = 4x – 20.

We have to solve the given equation in two methods, now let us see the first method.

<u><em>1st method ⇒ by subtracting 4x from both sides.</em></u>

Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 – 4x = 4x – 20 – 4x ⇒ -3x – 4x = -20 – 10 ⇒ -7x = -30 ⇒ 7x = 30  

Then, x = \frac{30}{7}

Now, let us use the 2nd method.

<em><u>2nd method ⇒ by adding 3x on both sides.</u></em>

Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 + 3x = 4x – 20 + 3x

⇒ 10 + 20 = 4x + 3x

⇒ 7x = 30

⇒ x = \frac{30}{7}

Hence, the value of x after solving in both methods is \frac{30}{7} = 4.2857.

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Answer:

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Step-by-step explanation:

In algebra, the word term refers to single numbers(10),  variables<em>(</em><em>y</em><em>)</em> also the product of the two(<em>10y</em>).

In the given expression : <em>ab+cd+ef+gh .</em>

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