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2 years ago

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Which equation represents an exponential function with an intitial value of 500? f(x) = 100(5)^x, f(x) = 100(x)^5, f(x) = 500(2)

^x, f(x) = 500(x)^2

1 answer:

Leya [2.2K]2 years ago

6 0

Answer:

f(x) = 500(2)^x

Step-by-step explanation:

Let's assume the initial x value is 0

500(0)^2 = 0

100(0)^5 = 0

500(2)^0 = 500

500(0)^2 = 0

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Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – 4x = 5

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Solve for x over the real numbers:
x^2 - 4 x = 5

Subtract 5 from both sides:
x^2 - 4 x - 5 = 0

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2 years ago

Read 2 more answers

An expression is given: 2 open parentheses square root of k minus 1 close parenthesis plus square root of 8. If on adding negati

neonofarm [45]

Answer:

Possible value of k is √2

Step-by-step explanation:

The information given are;

The expression, 2·(√k - 1) + √8 to which may be added -6·√2 to obtain a rational number, we therefore have;

2·(√k - 1) + √8 - 6·√2 = R

Therefore, simplifying gives;

2·√k - 2 + 2·√2 - 6·√2 = 2·√k - 2 - 4·√2 = R

2·√k - 2 - 4·√2 + 2= R + 2 = R

2·√k - 2+ 2 - 4·√2 = R

2·√k - 2+ 2 - 4·√2 = R

2·√k + 0 - 4·√2 = 2·√k - 4·√2 = 2·(√k - 2·√2) = R

(√k - 2·√2) = R/2 = R

Therefore, √2 is a factor of √k such that √k - 2·√2 = R

Which gives k = x·√2, where x = a rational number

When x = 1, k = √2.

Therefore, a possible value of k is √2

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2 years ago

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Answer:

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