Therefore 1364.69 should be rounded up to 1000.
An expression is given: 2 open parentheses square root of k minus 1 close parenthesis plus square root of 8. If on adding negati
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Capucine played a game where she earned 179 points from building 11 museums and 4 libraries.
Lets assume x points she earn per library
She earns 4 more points for museum than library.
4 more points per museum per x . so the points earned per museum is x+4
she earned 179 points from 11 museums and 4 libraries.
So the equation becomes
( subtract 44 from both sides)
(divide by 15 from both sides)
x = 9
She earns 9 points per library
We know points per museum = x+4 = 9+4 = 13
She earns 13 points per museum .