An expression is given: 2 open parentheses square root of k minus 1 close parenthesis plus square root of 8. If on adding negati
1 answer:
You might be interested in
The statements and their individual answers are not provided in the question. However, please check the explanation given below for the equation.
Step-by-step explanation:
- The equation given is
- Divide the leading term of the dividend by the leading term of the divisor:
- Multiply it by the divisor:
-
Subtract the dividend from the obtained result:
- Divide the leading term of the obtained remainder by the leading term of the divisor:
- Multiply it by the divisor:
- Subtract the remainder from the obtained result:
- Divide the leading term of the obtained remainder by the leading term of the divisor:
- Multiply it by the divisor:
- Subtract the remainder from the obtained result:
- Since the degree of the remainder is less than the degree of the divisor, then we are done.
- Therefore,
The summation indicates the sum from n = 1 to n = 3 of the expression 2(n+5).
2 (n+5) = 2n + 10
2n + 10 denotes an Arithmetic Series, with a common difference of two and first term as 12.
For n =1, it equals 12
For n = 2, it equals 14
For n = 3, it equals 16
So the sum from n=1 to n=3 will be 12 + 14 + 16 = 42
Sum of an Arithmetic Series can also be written as:
Using the value of a₁ and d, we can simplify the expression as:
This expression is equivalent to the given expression and will yield the same result.
For n=3, we get the sum as:
S₃ = 3(11+3) = 42
2 (n+5) = 2n + 10
2n + 10 denotes an Arithmetic Series, with a common difference of two and first term as 12.
For n =1, it equals 12
For n = 2, it equals 14
For n = 3, it equals 16
So the sum from n=1 to n=3 will be 12 + 14 + 16 = 42
Sum of an Arithmetic Series can also be written as:
Using the value of a₁ and d, we can simplify the expression as:
This expression is equivalent to the given expression and will yield the same result.
For n=3, we get the sum as:
S₃ = 3(11+3) = 42
Hello here is a soluion :
First off, let's find the 1st term's value, and the 30th term's value,
