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Dimas [21]
2 years ago
10

The table below shows the amount paid for different numbers of items. Determine if this relationship forms a direct variation. V

erify your answer.

Mathematics
1 answer:
Elden [556K]2 years ago
5 0
<h2>Answer/Step-by-step explanation:</h2>

Direct variation occurs when a variable varies directly with another variable. That is, as the x-variable increases, the y-variable also increases.

The ratio of between y-variable and x-variable would be constant.

Direct variation can be represented by the equation, y = xk, where k is a constant. Thus,

\frac{y}{x} = k

From the table given, it seems, as x increases, y also increases. Let's find out if there is a constant of proportionality (k).

Thus, ratio of y to x, \frac{0.50}{1} = 0.5

k = 0.5.

If the given table of values has a direct variation relationship, then, plugging in the values of any (x, y), into \frac{y}{x} = k, should give us the same constant if proportionality.

Let's check:

When x = 2, and y = 1:

\frac{y}{x} = k,

\frac{1}{2} = 0.5,

When x = 3, y = 1.5:

\frac{1.5}{3} = 0.5,

When x = 5, y = 2.50:

\frac{2.5}{5} = 0.5,

The constant of proportionality is the same. Therefore, the relationship forms a direct variation.

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A region R in the xy-plane is given. Find equations for a transformation T that maps a rectangular region S in the uv-plane onto
ruslelena [56]
X(u, v) = (2(v - c) / (d - c) + 1)cos(pi * (u - a) / (2b - 2a))
y(u, v) = (2(v - c) / (d - c) + 1)sin(pi * (u - a) / (2b - 2a))

As v ranges from c to d, 2(v - c) / (d - c) + 1 will range from 1 to 3, which is the perfect range for the radius. As u ranges from a to b, pi * (u - a) / (2b - 2a) will range from 0 to pi/2, which is the perfect range for the angle. So, this maps the rectangle to R.
6 0
2 years ago
Write the number described by 1 ten 16 one
AVprozaik [17]

Answer:

26

Step-by-step explanation

There is ONE ten

There is SIXTEEN ones

Just add 10 and 16 together to get 26.

8 0
2 years ago
Triangle R T S is sitting on a horizontal line. Line S R extends through point Q to form exterior angle T R Q. Angle R T S is (2
Firlakuza [10]

Answer:

The value of x is 3 ⇒ 2nd answer

Step-by-step explanation:

<u><em>An exterior angle</em></u> is the angle between one side of a triangle and the

extension of an adjacent side

<u><em>The measure of an exterior angle at any vertex of a triangle equal the </em></u>

<u><em>sum of the measures of the two opposite interior angles</em></u>

- Triangle R T S is sitting on a horizontal line

- Line S R extends through point Q to form exterior angle T R Q

- m∠RTS is (25 x)°, m∠TSR is (57 + x)° , m∠TRQ is (45 x)°

* Lets find the value of x

∵ ∠TRQ is an exterior angle of Δ RTS at the vertex R

∵ The opposite interior angles to vertex R are ∠RTS and ∠TSR

∴ m∠TRQ = m∠RTS + m∠TSR ⇒ <u><em>as the rule above</em></u>

∵ m∠TRQ = (45 x)°

∵ m∠RTS = (25 x)°

∵ m∠TSR = (57 + x)°

Substitute these measures in the equation above

∴ 45 x = 25 x + 57 + x

∴ 45 x = 26 x + 57

Subtract 26 x from both sides

∴ 19 x = 57

Divide both sides by 19

∴ x = 3

* The value of x is 3

3 0
2 years ago
Read 2 more answers
Two random samples are taken from private and public universities
kati45 [8]

Answer:

Step-by-step explanation:

For private Institutions,

n = 20

Mean, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (43120 - 34623.05)^2+ (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public Institutions,

n = 20

Mean, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Summation(x - mean)² = (25469 - 25063.15)^2+ (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

s2 = 3766.55

This is a test of 2 independent groups. Let μ1 be the mean out-of-state tuition for private institutions and μ2 be the mean out-of-state tuition for public institutions.

The random variable is μ1 - μ2 = difference in the mean out-of-state tuition for private institutions and the mean out-of-state tuition for public institutions.

We would set up the hypothesis. The correct option is

-B. H0: μ1 = μ2 ; H1: μ1 > μ2

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

We would determine the probability value from the t test calculator. It becomes

p value = 0.000065

Since alpha, 0.01 > than the p value, 0.000065, then we would reject the null hypothesis. Therefore, at 1% significance level, the mean out-of-state tuition for private institutions is statistically significantly higher than public institutions.

4 0
2 years ago
A dog has dug holes in diagonally-opposite corners of a rectangular yard. One length of the yard is 8 meters and the distance be
LUCKY_DIMON [66]

For a better understanding of the solution provided please go through the diagram in the file attached.

Let ABCD be the rectangular yard. The diagonal d=17 meters. AD=8 meters. Therefore, the length of DC can be found by applying the Pythagorean theorem in the right triangle \Delta ADC as:

DC=\sqrt{17^2-8^2}=\sqrt{(AC)^2-(AD)^2}=\sqrt{225} =15 meters.

6 0
2 years ago
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