Work out (7x10^5)divide(2x10^2) give your answer in standard form (I WILL GIVE BRAINLIEST)
1 answer:
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Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.
Answer:
Step-by-step explanation:
given that tonya charges 20$ monthly fee and 3$ per mile of her dog-walking service.
and beth does not charge any monthly fee but charges 5$ per mile of the dog walked in.
let x be the number of miles dog has walked in a month.
the amount tonya will charge on x miles = fixed monthly fee + number of miles * charge per mile = 20+3x
and the amount beth will charge on x miles = 0+ 5*x = 5x.
we are asked to find the x-value for which beth chargeable amount = tonya chargeable amount
that is 5x = 20+3x
5x-2x = 20
2x=20
x=
hence number of miles for which tonya and beth will charge the same amount is 10.