Joanna has nickels, dimes, and pennies in a jar. The probability of drawing a nickel from the jar is 0.3, the probability of dra
2 answers:
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Set up hypotheses:
The null hypotheses is that the proportion of readers who own a Rolls Royce is equal to 0.55
Null hypotheses = H₀: p = 0.55
The alternate hypotheses is that the proportion of readers who own a Rolls Royce is not equal to 0.55
Alternate hypotheses = H₁: p ≠ 0.55
Determine the type of test:
Since the alternate hypothesis states that the proportion of readers who own a Rolls Royce is different, therefore it is a two-tailed test.
Determine the level of significance and Critical Z-score:
Given level of significance = 0.05
Since it is a two-tailed test,
Z-score = 1.960 (two tailed)
Set up decision rule:
Since it is a two-tailed test, using a Z statistic at a significance level of 5%
We Reject H₀ if Z < -1.960 or Z > 1.960
We Reject H₀ if p ≤ α
Compute the test statistic:
The test statistic may be calculated using,
We are not given enough information to find out the test statistic.
Conclusion:
We do not have enough information to accept or refuse the publisher's claim.
Actually there is enough information to solve this problem. First, let us find the total per row and per column.
(see attached pic)
P(Grade 10 | opposed) with P(opposed | Grade 10)
P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)
P(Grade 10 | opposed) = 13 / 41 = 0.3171
P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)
P(opposed | Grade 10) = 13 / 32 = 0.4063
Therefore:
P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.
Answer:
P(Grade 10 | opposed) < P(opposed | Grade 10)
