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Mrac [35]
2 years ago
12

A library has six identical copies of a certain book. At any given time, some of these copies are at the library and some are ch

ecked out. How many different ways are there for some of the books to be in the library and the rest to be checked out if at least one book is in the library and at least one is checked out? (The books should be considered indistinguishable.)
Mathematics
1 answer:
lions [1.4K]2 years ago
4 0
5 different ways I believe
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Jack was so frustrated with his slow laptop that he threw it out of his second story window. The height, h, of the laptop at tim
jeyben [28]

Answer:

The domain of the function is the interval [0,2.23]

see the explanation

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> the height of the laptop in units

we have

h(t)=-16t^{2}+28t+17

we know that

When the laptop hits the ground, the value of h(t) is equal to zero

so

For h(t)=0

-16t^{2}+28t+17=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+28t+17=0

so

a=-16\\b=28\\c=17

substitute in the formula

x=\frac{-28(+/-)\sqrt{28^{2}-4(-16)(17)}} {2(-16)}

x=\frac{-28(+/-)\sqrt{1,872}} {-32}

x=\frac{-28(+/-)12\sqrt{13}} {-32}

x_1=\frac{-28(+)12\sqrt{13}} {-32}=-0.477

x_1=\frac{28(-)12\sqrt{13}} {32}=-0.477  ---> is not a solution

x_2=\frac{-28(-)12\sqrt{13}} {-32}

x_2=\frac{28(+)12\sqrt{13}} {32}=2.23\ sec

therefore

The domain of the function is the interval [0,2.23]

All real numbers greater than or equal to 0 seconds and less than or equal to 2.23 seconds

0\ sec \leq x \leq 2.23\ sec

5 0
2 years ago
Cindy’s parking garage charges $3.50 for weekday parking, and weekends are half price. If Cindy parked in the garage 20 times pe
Pachacha [2.7K]

Answer: \$64.75

Step-by-step explanation:

  You know that for weekdays parking the price is $3.50 and weekends are half price.  Then for weekends, the price is the following:

\frac{\$3.50}{2}=\$1.75

You know that Cindy parked in the garage 20 times per month, and three of these days were weekend days. This means that she parked 17 times in week days and 3 times in weekends days.

 Therefore, the total amount of money she would spend on parking per month can be calculated with:

Total\ per\ month=17(\$3.50)+3(\$1.75)\\\\Total\ per\ month=\$59.5+\$5.25\\\\Total\ per\ month=\$64.75

6 0
2 years ago
11) Which situation can be represented by 17.35x > 624.60?
agasfer [191]

Answer:

  J Darren earns $17.35 per hour at his job. How many hours does he need to work in order to earn more than $624.60?

Step-by-step explanation:

You're looking for a situation in which the number 17.35 needs to be multiplied by an unknown quantity.

Scenarios F and G involve addition of 17.35 to something.

Scenario H would correspond to the inequality ...

  17.65x < 624.60

The sign of the given inequality is >, so scenario H is not the one.

__

In scenario J, Darren's total earnings for x hours will be 17.35x, and we want to find x such that this total is greater than 624.60. This matches the given inequality:

  17.35x > 624.60 . . . . . . answer choice J

6 0
2 years ago
Last year a banquet hall charged $65 per person to attend a function. The function C(p) = 65p represents the total cost, C, to r
zlopas [31]

Answer:

Domain = [0, 50]

Range   = [0, 3250]

Step-by-step explanation:

A function shows the relationship between two variables (independent variable and dependent variable). The independent variable is a variable not dependent on any variable, it is the input of the function while the dependent variable is a variable dependent on other variable, it is the output of the function.

The domain of a function is the set of all input variables (independent variable) and the range of a function is the set of all output variables (dependent variables).

In the function C(p) = 65p, p is the independent variable and C(p) is the dependent variable.

Since the hall can hold a total of 50 people, the domain of the function = [0, 50]

C(0) = 65(0) = 0, C(50) = 65(50) = 3250

Hence, the range of the function = [0, 3250]

8 0
2 years ago
The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 4 m
geniusboy [140]
We take the distance from points which indicates the location of the park and the mall.

For distance through north and east, we have positive values and negative for west and south. 

Mall:   (-3, -4)
Park:   (3, 5)

The distance is calculate through the equation,
                      d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)

Substituting,
                      d = sqrt ((-4 - 5)² + (-3 - 3)²
                             d = sqrt 117 = 10.82
Thus, the distance between the mall and the park is approximately 10.82 miles. 
5 0
2 years ago
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