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Leviafan [203]
2 years ago
6

Which statement is true regarding the graphed functions?

Mathematics
2 answers:
BARSIC [14]2 years ago
8 0
C . you can look them up in graphs
padilas [110]2 years ago
4 0

Answer:

C

Step-by-step explanation:

You can look them up in the graphs.

f(2) means "where is the blue graph when x=2?", and you can see it is at y=0.

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What is the time period of a loan for $2,500 at 12% exact interest if the amount of interest is $118.36? Round to the next highe
Marianna [84]
I believe it's 144 days.

Hope this helped!
5 0
2 years ago
Read 2 more answers
Solve 11 - 1/2y= 3 + 6x for y.​
Ilia_Sergeevich [38]

Answer:

y = 12x+16

Step-by-step explanation:

Simplify both sides of the equation then isolate the variable.

Step 1, add 11 to both sides.

−1 /2 y+11+−11=6x+3+−11

−1 /2 y=6x−8

Step 2, divide both sides by (-1)/2.

You will be left with

y = 12x+16

3 0
2 years ago
Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

3 0
2 years ago
The polynomial equation x cubed minus 4 x squared + 2 x + 10 = x squared minus 5 x minus 3 has complex roots 3 plus-or-minus 2 i
Tpy6a [65]

Answer: Answer is B, -1

Step-by-step explanation:

This is the correct answer according to Edge

This should be a five star btw sorry

7 0
2 years ago
Read 2 more answers
Three trigonometric functions for a given angle are shown below. cosecant theta = thirteen-twelfths; secant theta = Negative thi
Kay [80]

Answer:

(–5, 12) is the correct answer.

Step-by-step explanation:

We are given the following values:

cosec\theta = \dfrac{13}{12}\\sec\theta=-\dfrac{13}{5}\\cot\theta =-\dfrac{5}{12}

Now, we know the following identities:

sin \theta = \dfrac{1}{cosec\theta}\\cos \theta = \dfrac{1}{sec\theta}\\tan \theta = \dfrac{1}{cot\theta}

Now, the values are:

sin\theta = \dfrac{12}{13}\\cos\theta=-\dfrac{5}{13}\\tan\theta =-\dfrac{12}{5}

Sine value is positive and cos, tan values are negative.

It can be clearly observed that \theta is in 2nd quadrant.

2nd quadrant means, the value of x will be negative and y will be positive.

Let us have a look at the value of tan\theta:

tan\theta  = \dfrac{Perpendicular}{Base}\\OR\\tan\theta  = \dfrac{y-coordinate}{x-coordinate} = -\dfrac{12}{5}\\\therefore y = 12,\\x = -5

Please refer to the attached image for clear understanding and detailed explanation.

Hence, the correct answer is coordinate (x,y) is (–5, 12)

8 0
2 years ago
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