Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
1 answer:
Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
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Answer:
$311.74
Step-by-step explanation:
A financial calculator computes the payment amount to be $311.74.
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Your graphing calculator may have the capability to do this. Certainly, such calculators are available in spreadsheet programs and on the web.
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The appropriate formula is the one for the sum of terms of a geometric series.
Sn = a1·((1+r)^n -1)/(r) . . . . . where r is the monthly interest rate (0.005) and n is the number of payments (480). Filling in the given numbers, you have ...
$620827.46 = a1·(1.005^480 -1)/.005 = 1991.4907·a1
Then ...
$620827.46/1991.4907 = a1 ≈ $311.74
