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Delicious77 [7]

1 year ago

5

Ten boys agree to paint the gym in 5 days. If five more boys join in before the work begins, how many days should the painting t

ake?
A. 3 1/3
B. 3 1/2
C. 2 1/2
D. 2 3/4

2 answers:

Kay [80]1 year ago

6 0

The answer to this question is 30

Ganezh [65]1 year ago

3 0

Answer:

30

Step-by-step explanation:

You might be interested in

Test 24,515 for divisibility by 2, 3, 5, 9, or 10.

lord [1]

Answer:

D

Step-by-step explanation:

1. When a number is divisible by 2 it must end with even digit 0, 2, 4, 6 or 8.

So the number 24,515 is not divisible by 2.

2. When a number is divisible by 5 it must end with digit 0, or 5.

The number 24,515 ends with 5 so it is divisible by 5.

3. When a number is divisible by 3, the sum of all digits must be divisible by 3.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 3, so the number 24,515 is not divisible by 3.

4. When a number is divisible by 9, the sum of all digits must be divisible by 9.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 9, so the number 24,515 is not divisible by 9.

5. When a number is divisible by 10 it must end with digit 0.

The number 24,515 ends with 5 so it is not divisible by 10.

8 0

1 year ago

The system shown is _____.<br><br> equivalent<br><br> independent<br><br> inconsistent

Rzqust [24]

We know that
If a system has at least one solution, it is said to be consistent.
When you graph the equations, both equations represent the same line
so
the system has an infinite number of solutions

If a consistent system has an infinite number of solutions, it is dependent.
<span>
therefore
the system is </span>consistent, dependent and <span>equivalent
</span><span>
the answer is
</span>equivalent

3 0

1 year ago

Read 2 more answers

Which equations are equivalent to Three-fourths + m = negative StartFraction 7 over 4 EndFraction? Select three options. m = Sta

marishachu [46]

Answer:

1) m = negative StartFraction 10 over 4 EndFraction

2) m = negative five-halves

3) m = $-\frac{7}{4} - \frac{3}{4}$

Step-by-step explanation:

<u>The given equation is:</u>

=> $\frac{3}{4} +m = -\frac{7}{4}$

Subtracting 3/4 to both sides

=> m = $-\frac{7}{4} - \frac{3}{4}$

=> m = $\frac{-10}{4}$

=> m = $-\frac{5}{2}$

5 0

1 year ago

Read 2 more answers

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

1 year ago

Mrs. Start's class paid $5.60 for 4 5 yd of lace for an art project. Later, the class decided to buy another 7 3 4 yd of the sam

Damm [24]

The answer to your question, is 54.25.

3 0

1 year ago