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tangare [24]
1 year ago
10

Test 24,515 for divisibility by 2, 3, 5, 9, or 10.

Mathematics
1 answer:
lord [1]1 year ago
8 0

Answer:

D

Step-by-step explanation:

1. When a number is divisible by 2 it must end with even digit 0, 2, 4, 6 or 8.

So the number 24,515 is not divisible by 2.

2. When a number is divisible by 5 it must end with  digit 0,  or 5.

The number 24,515 ends with 5 so it is divisible by 5.

3. When a number is divisible by 3, the sum of all digits must be divisible by 3.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 3, so the number 24,515 is not divisible by 3.

4. When a number is divisible by 9, the sum of all digits must be divisible by 9.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 9, so the number 24,515 is not divisible by 9.

5. When a number is divisible by 10 it must end with  digit 0.

The number 24,515 ends with 5 so it is not divisible by 10.

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A formula for 6 gallon of light green paint use 3/8 gallons of white paint. Liam has 9/16 gallon of white paint. Does liam have
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Answer:

Yes he have enough white paint.

Step-by-step explanation:

We are given

6 gallons of light green paint use → \frac{3}{8} gallons of white paint

using the unitary method

1 gallons of white paint → 6*8/3 gallons of light green paint

                                        → 16 gallons of light green paint

but Liam have 9/16 gallons of white paint

9/16 gallons of white paint → 16* 9/16 gallons of light green paint

                                             → 9 gallons of light green paint

Yes Liam have enough white paint to make 8 gallons of light green paint.  

3 0
2 years ago
What is the sum of the distinct prime factors of 315
Nuetrik [128]

Answer: The exponents in the prime factorization are 2, 1, and 1. Adding one to each and multiplying we get (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12. Therefore 315 has exactly 12 factors.

Step-by-step explanation: First, the exponents in the prime factorization are 2, 1, and 1. Then adding one to each and multiplying we get (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12. Finally, 315 has exactly 12 factors.

7 0
2 years ago
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

5 0
2 years ago
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Answer:

Kim's business earns $10,000 per month.

Kim's non-employee expenses are $3,000 per month.

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If each employee costs $1,000 per month, Kim can recruit 5000/1000 = 5 as the maximum number of employees.

Hope this helps

:)

8 0
2 years ago
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