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ivann1987 [24]
2 years ago
7

Mrs. Start's class paid $5.60 for 4 5 yd of lace for an art project. Later, the class decided to buy another 7 3 4 yd of the sam

e lace to make costumes for the school musical. How much money do they need for this second purchase?
Mathematics
1 answer:
Damm [24]2 years ago
3 0
The answer to your question, is 54.25.
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A 4-ounce cup of coffee costs $8.00. How much would a 3-ounce cup of cofee codt?
romanna [79]
To solve this, we must first find out the cost-per-ounce of a cup of coffee. Assuming that the rates are flat, then we can just divide the 8-dollar-cost by the 4-ounce cup that it buys.

8 / 4 = 2

The cost-per-ounce of a cup of coffee is $2.
Now, we just have to multiply the cost-per-ounce by the amount of coffee we want to find out the cost of.

2 * 3 = 6

With all else constant, a 3-ounce cup of coffee would cost $6.
Hope that helped! =)
5 0
2 years ago
Read 2 more answers
The Patel family went apple picking. The number of red apples they picked was 2 __ 2 9 times the number of green apples they pic
miskamm [114]

Answer:

100

I first made 45 a fraction = 45/1

Then i made 2 2/9 into an improper fraction

then make my equation

45/1 ×20/9=100

answer is 100 red apples

Step-by-step explanation:

6 0
2 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
2 years ago
A. imagine that you are one of the people who left the luncheon with a contagious disease and interacted with an average of 9 di
shusha [124]

1.       In line with the test each person who came into interaction with the infected person will become infected also. With this information, the calculation would be: 9 people each day for 7days would be equivalent to 9 x 7 which equals 63 people.

2.       Here were 7 other people in the experiment if patient zero is left out. If each person intermingled with 6 different people every day in 7 days then the calculation would be: 7 people infected x 6 new people = 42 infected people each day

42 new people every day x 7 days = 294 infected persons.

8 0
2 years ago
Chuck has a gross pay of $815.70. By how much will Chuck’s gross pay be reduced if he has the following items withheld? federal
tangare [24]

Chuck has a gross pay of $815.70. His gross pay will be reduced by:

  • Federal tax of $56;
  • Social Security tax that is 6.2% of his gross pay;
  • Medicare tax that is 1.45% of his gross pay;
  • State tax that is 19% of his federal tax.

Let's count:

1. gross pay of $815.70 - 100%,

Social Security tax of $x - 6.2%.

Then

\dfrac{815.70}{x}=\dfrac{100}{6.2} ,\\ \\815.70\cdot 6.2=x\cdot 100,\\ \\x=\dfrac{815.70\cdot 6.2}{100} =50.5734.

2. gross pay of $815.70 - 100%,

Medicare tax of $y - 1.45%.

Then

\dfrac{815.70}{y}=\dfrac{100}{1.45} ,\\ \\815.70\cdot 1.45=y\cdot 100,\\ \\y=\dfrac{815.70\cdot 1.45}{100} =11.82765.

3. Federal tax of $56 - 100%,

State tax $z - 19%.

Then

\dfrac{56}{z}=\dfrac{100}{19} ,\\ \\56\cdot 19=z\cdot 100,\\ \\z=\dfrac{56\cdot 19}{100} =10.64.

4. Chuck’s gross pay will be reduced by

\$56+\$50.5734+\$11.82765+\$10.64=\$129.04105\approx \$129.04.

3 0
2 years ago
Read 2 more answers
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