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trasher [3.6K]
2 years ago
15

Use properties to rewrite the given equation. Which equations have the same solution as 2 3p-10.1 = 6.5p - 4 - 0.01p? Select two

options
2.3p - 10.1 = 6.4p - 4
2.3p - 10.1 = 6.49p - 4
230p-1010 = 650p-400-P
23p - 101 = 65p - 40-P
O 2.3p - 14.1 = 6.4p - 4
Mathematics
2 answers:
SSSSS [86.1K]2 years ago
7 0

2.3p - 10.1 = 6.5p - 4 - 0.01p

If we multiply this equation by 100 we have

230p - 1010 = 650p - 400 - p

So the right answer is this

tangare [24]2 years ago
4 0

Answer:

Should be B &C

Step-by-step explanation:

Answer on Edgenuity

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Agent Hunt transferred classified files from the CIA mainframe onto his flash drive. The drive had some files on it before the t
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Answer:   The drive was 24.32% full when the transfer began.

 

Step-by-step explanation:

Given: The rate of transferring file = 4.44 megabytes per second.

After 32 seconds, the amount of data on the drive = 384 megabytes  

The amount of transferred data = 32\times4.4=140.8 megabytes  

Therefore, the amount of data in the drive at the beginning is given by :-

\text{Beginning amount=Amount after 32 seconds -Amount transferred}\\\\\Rightarrrow\ \text{Beginning amount=}384-140.8=243.2

The drive had a maximum capacity of 1000 megabytes.

\frac{243.2}{1000}\times100=24.32\%

Hence, the drive was 24.32% full when the transfer began.

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1 year ago
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Kevin has had a checking account for a month. As he reconciles his account, Kevin notices that the dates on his check register d
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The most likely answer is D) <span>"The date that the check is written is usually a few days before it is cashed. We record when it was cashed and you record when its written". 

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2 years ago
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Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model
Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

\text{F}_(_n__1-1, n_2-1_)

Here, n_1 = sample of 15 Claiborne models

         n_2 = sample of 12 Klein models

So, the degrees of freedom = (n_1-1, n_2-1) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The test statistics that will be used here is F-test which is given by;

                          T.S. = \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ \text{F}_(_n__1-1, n_2-1_)

where, s_1^{2} = sample variance of the Claiborne models data = \frac{\sum (X_i-\bar X)^{2} }{n_1-1} = 1.007

s_2^{2} = sample variance of the Klein models data = \frac{\sum (X_i-\bar X)^{2} }{n_2-1} = 2.653    

So, the test statistics =  \frac{1.007}{2.653 } \times 1  ~ \text{F}_(_1_4,_1_1_)

                                   = 0.3796

Hence, the value of the test statistic is 0.3796.

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Answer:

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Step-by-step explanation:

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