answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katovenus [111]
2 years ago
15

Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len

gth of the conferences was 3.94 days, with a standard deviation of 1.28 days. Assume the underlying population is normal. What is the error bound of 95% confidence interval for the population mean length of engineering conferences? Construct a 95% confidence interval for the population mean length of engineering conferences. What is the lower bound? Construct a 95% confidence interval for the population mean length of engineering conferences. What is the upper bound?
Mathematics
1 answer:
Marina86 [1]2 years ago
6 0

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]±Z_{1-\alpha/2}*(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

You might be interested in
30,45,x,100; The median is 51
Alex Ar [27]
To solve for x, you must first understand how the median was calculated out of the given set of numbers. Without looking at the given median value, we can see that we cannot get the median by process of elimination since there are an even amount of numbers in this particular set. Therefore, we must average the two closest values to what should be the median.

In this case, the values are "45" and "x". If we pretend that we know the value of the variable "x" (for example we will pretend that x is 55), then we should have an equation that looks like this: (45+55) ÷ 2 = [median]. What this equation is doing is adding the two closest values to the median (45 and 55) and dividing it by 2, the number of values we are averaging. Now we can solve this equation and simplify it to 100 ÷ 2 which is 50, our median.

So if they give us the median instead of the x value, then we can rewrite the equation to fit your request: (45+x) ÷ 2 = 51. Now we can solve for x:

1. Multiply by 2
(45+x) = 102

2. Subtract 45
x = 57

The x value for your question is 57.
3 0
2 years ago
Read 2 more answers
Find the product of 0.094 ×0.367
Keith_Richards [23]
0.034498 is the answer
3 0
2 years ago
Select the coordinates of two points on the line y= 8
notsponge [240]
The answer for this is (0,8) and (8,0)
7 0
2 years ago
Read 2 more answers
Mason used a 30% coupon to buy a new computer. After the discount, the cost of the computer was $728.
shtirl [24]

Answer:

The original price of computer is $ 1040

Solution:

Given that, Mason used a 30% coupon to buy a new computer

After the discount, the cost of the computer was $728

To find: original price of computer

From given question,

price after discount = $ 728

discount = 30 % of original price

Let "x" be the original price of computer

price after discount = original price - discount price

Step-by-step explanation:

5 0
1 year ago
In a basketball arena, all four sides are filled with people. If each side of the arena is 20 ft. X 30 ft., and each person take
nasty-shy [4]

Answer:

<h2><em><u>960 people </u></em></h2>

Step-by-step explanation:

If each side of the basketball arena is 20 ft. X 30 ft, the area of each side of the basketball arena = 20ft * 30ft = 600ft².

Since all the four sides are filled with people, the total area of the 4 sides will be expressed as 4*600 = 2400ft²

If each person takes up 2.5ft², total number of people in the arena will  be gotten by simply dividing the area of all the four sides by the area took up by each person.

Total number of people in the arena = area of all the four sides by the area/ area took up by each person.

Total number of people in the arena = 2400/2.5

Total number of people in the arena  = 960 people.

<em><u></u></em>

<em><u>Hence there are approximately 960 people in the arena.</u></em>

8 0
2 years ago
Other questions:
  • Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain
    10·2 answers
  • Part a
    15·1 answer
  • A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimension
    12·2 answers
  • The graph below could be the graph of which exponential function?
    9·2 answers
  • Leo needs 10 red roses and 15 pink daisies for every 5 bouquets he makes for a flower shop. Drag red roses and pink daisies into
    9·2 answers
  • What is the value of x in the equation below? –3 – (–8) – (–2) = x
    15·1 answer
  • ) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
    7·1 answer
  • In circle D, ∠EDH ≅ ∠EDG. Circle D is shown. Line segment F H is a diameter. Line segments D E and D G are radii. Lines are draw
    14·1 answer
  • As a promotional offer, a new gym is offering a 30% discount to those who sign up in the first month. Patty and her 2 siblings t
    11·2 answers
  • What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is Two-thirds the length of t
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!