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kari74 [83]
2 years ago
7

30,45,x,100; The median is 51

Mathematics
2 answers:
Alex Ar [27]2 years ago
3 0
To solve for x, you must first understand how the median was calculated out of the given set of numbers. Without looking at the given median value, we can see that we cannot get the median by process of elimination since there are an even amount of numbers in this particular set. Therefore, we must average the two closest values to what should be the median.

In this case, the values are "45" and "x". If we pretend that we know the value of the variable "x" (for example we will pretend that x is 55), then we should have an equation that looks like this: (45+55) ÷ 2 = [median]. What this equation is doing is adding the two closest values to the median (45 and 55) and dividing it by 2, the number of values we are averaging. Now we can solve this equation and simplify it to 100 ÷ 2 which is 50, our median.

So if they give us the median instead of the x value, then we can rewrite the equation to fit your request: (45+x) ÷ 2 = 51. Now we can solve for x:

1. Multiply by 2
(45+x) = 102

2. Subtract 45
x = 57

The x value for your question is 57.
son4ous [18]2 years ago
3 0

Answer:

x = 57

Step-by-step explanation:

Median is the number that is halfway mark. If we are given a data, first we need to arrange them in ascending order and take the middle value. That is called median.

If we have odd number of data, we can easily find the middle value.

For instance, 1, 2, 3, 4, 5 here the number of data = 5 which is odd number.

The middle number is 3.

Therefore, median is 3.

If we have even number of data, we have to take middle two values, add them then divide by 2.

In this case, we are given even number of data

30, 45, x, 100

4 data which is even number of data.

Median is given as 51, we need to find the value of x.

The middle two numbers are 45 and x, we have to add them and divide by 2

Median = \frac{45 + x}{2}       [Given: median = 51]

51 = \frac{45 + x}{2}

Multiplying both sides by 2, we get

51*2 = 45 + x

102 = 45 + x

Subtract 45 in both sides, we get

102 - 45 = 45 -45 + x

x = 102 -45

x = 57

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c

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Charlotte is redecorating the master bedroom in her house. She has already purchased a new bedroom set and also plans to paint t
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Answer:

a. 30%

b. $893.59

c.

\frac{(351.10-x)}{893.59}\times 100\%

Step-by-step explanation:

a. Given that the carpet costs $427.35, the labor costs $212.52 and other flooring supplies costs $75.

#To get the  percent of the flooring bill that will go towards the cost of labor:

\%  labor\ cost=\frac{labor \ cost}{Total \ flooring \ cost}\times 100\%\\\\=\frac{212.52}{427.35+212.52+75}\times 100\%\\\\=\frac{212.52}{714.87}\times 100\%\\\\=29.73\%\approx30\%

Hence, labor costs 30% of the total flooring costs.

b.The total flooring costs is :

F_c=212.52+427.35+75\\\\=714.87

Given that she spends 25% more on furniture than on flooring, we multiply the flooring cost by 125% to get the furniture costs:

Furniture \ Cost= Flooring \ C\ost \times 125%\\\\=714.87\times 1.25\\\\=893.59

Hence, she spends $893.59 on furniture.

c.To get what percentage of  furniture cost was the night stand.

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Let x be the cost of the dresser and y the cost of the nightstand;

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The percentage is then calculated as:

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Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the varia
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Answer:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property.

Step-by-step explanation:

Given the polynomial :

80b⁴ – 32b²c³ + 48b⁴c

The Greatest Common Factor (GCF) of the coefficients:

80, 32, 48

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80

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48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

GCF = 16

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GCF of c³ and c

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We can see that David's GCF of the coefficients are all correct

From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect

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center\ ({{ h}},{{ k}})\\
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c=\textit{distance from the center to either foci}\\\\
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now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

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