Given that μ=0, and σ=1, P(z>c)=0.1093
thus
P(z<c)=1-0.1093=0.8907
hence the value of c will be:
z-score=(c-μ)/σ
thus
1.23=(c-0)/1
c=1.23
Answer: E) Mean will decrease, standard deviation will decrease
Step-by-step explanation:
Initial mean = 81
Initial standard deviation = 9
New score = 78
Taking a look at the initial mean(averahe) score, which is 81 and the new score to be added to the initial scores, the initial average is greater than the new score. Hence, this will result in a decrease in the new mean score after adding the new score of 78.
Also, taking a look at the standard deviation which is 9, we can conclude that the variability in initial scores from the mean scores is high. However, the new score of 78 and the initial mean are very close, and tend to low variation. Hence, adding the new score will lead to a decrease in variability and hence a decrease in the value of standard deviation.
Answer:
On a coordinate plane, a dashed straight line with negative slope goes through (negative -5/3, 0) and (0, negative 5). Everything to the right of the line is shaded
Step-by-step explanation:
6x + 2y > –10
Solve for y
Subtract 6x from each side
2y > -6x -10
Divide by 2
y > -3x - 5
The y intercept is -5 and the slope is -3
The x intercept is -5/3
The line is dashed and shaded to the right
I assume you mean -x^3 + 4x + 3
so what you need is 4x + 3 > x^3
the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2
