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mestny [16]
2 years ago
7

What is m? 49° 77° 98° 161°

Mathematics
2 answers:
Mariana [72]2 years ago
4 0

we know that

The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.

In this problem

21\°=\frac{1}{2}[arc\ RU-arc\ SU]

Solve for the measure of arc SU

42\°=[arc\ RU-arc\ SU]

arc\ SU=arc\ RU-42\°

arc\ SU=119\°-42\°=77\°

therefore

the answer is

The measure of the arc SU is 77\°

andrey2020 [161]2 years ago
4 0

Answer:

77

Step-by-step explanation:

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<h2>Part 1.</h2>

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\boxed{f'(x)=3x^2-8x}

<h2>Part 2.</h2>

Answer: \boxed{y=3x-16}

The equation of the line that passes through the same point can be found as:

y-y_{0}=m(x-x_{0})

Where x_{0}=3, so we need to find y_{0}. Plug in that x-value in the function we have:

y_{0}=f(3)=(3)^3-4(3)^2+2 \\ \\ y_{0}=-7 \\ \\ \\ So \ the \ point \ is: \\ \\ P(x_{0},y_{0})=(3,-7)

And the slope is:

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Then, the equation of the line is:

y-(-7)=3(x-3) \\ \\ \therefore y+7=3x-9 \\ \\ \boxed{y=3x-16}

<h2 /><h2>Part 3.</h2>

Answer: Shown below

As you can see below, the graph of the function of f is continuous. This is so because we have plotted a polynomial function whose domain is the set of all real numbers. So the function is defined at the point P(3,-7), so the derivative exists at this point, hence we can calculate a tangent line there. In conclusion, we get the graph shown below. The blue line is the tangent line while the red curve is the graph of f

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