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Gemiola [76]
2 years ago
5

Lana and Jeff each randomly surveyed 15 students about their favorite types of movies. What would you expect to see in the sampl

es? Select all that apply.
Mathematics
1 answer:
Anon25 [30]2 years ago
3 0

Answer:

  1. Listing of 15 students
  2. Assignment of a sequential number to each student.
  3. The figured out sample size, i.e., 2.
  4. Selected sample using sampling frame 15 from Step 2 and your sample size from Step 3, i.e., 2  

Step-by-step explanation:

Random sampling is a piece of the sampling method where each example has an equivalent likelihood of being picked. An example picked randomly is intended to be an impartial portrayal of the all out populace. On the off chance that for certain reasons, the example doesn't speak to the populace, the variety is known as a sampling mistake. A random example is an example that is picked randomly. It could be all the more precisely called a randomly picked test. Random examples are utilized to stay away from inclination and other undesirable impacts. Random sampling is probably the least complex type of gathering information from the all out populace. Under random sampling, every individual from the subset conveys an equivalent chance of being picked as a piece of the sampling procedure.

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In a large population, 61 % of the people have been vaccinated. if 4 people are randomly selected, what is the probability that
muminat
In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.

For only one person, we use P(1), same reasoning should hold for other subscripts.

P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841

Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
8 0
1 year ago
Two production lines produce the same parts per week of which 100 are defective. Line 2 produces 2,000 parts per week of which 1
Vikentia [17]

Answer:

(a) 0.0833 or 8.33%

(b) 0.40 or 40%

Step-by-step explanation:

Parts line one (n1) = 1,000 parts

Defects line one (d1) = 100 parts

Parts line two (n2) = 2,000 parts

Defects line two (d2) = 150 parts

Total number of parts (n) = 3,000 parts

a. Probability of a randomly selected part being defective:

P(d) = \frac{d_1+d_2}{n_1+n_2}=\frac{100+150}{1,000+2,000}\\P(d) =0.0833=8.33\%

The probability is 0.0833 or 8.33%

b. Probability of a part being produced by line one, given that it is defective:

P(1|d)=\frac{P(1\cap d)}{P(1\cap d)+P(2\cap d)}\\P(1|d)=\frac{\frac{100}{3,000} }{\frac{100}{3,000}+\frac{150}{3,000}}\\P(1|d)=0.4 = 40\%

The probability is 0.40 or 40%.

5 0
1 year ago
Solve 10m -28 = 6 -7m​
Finger [1]

Answer:

Step-by-step explanation:

5 0
2 years ago
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Can someone please help?? I know how to get this problem started but I can't seem to do the entire thing. Thank you.
Klio2033 [76]

Answer:

A: 20

B. 34

Step-by-step explanation:

5 0
2 years ago
Amy has two older brothers. Ben is 3 years older than Amy. Chris is 10 years older than Ben. The total of their ages is 73. Form
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73-(10+3)=60 you have to add 7 and 3 first, then you subtract it from 73
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2 years ago
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