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RSB [31]
2 years ago
5

Write $\frac{99}{100}\cdot(0.\overline{4})$ as a fully simplified fraction.

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
6 0

Answer:

  • \frac{11}{25}

Explanation:

The expression that must be rewritten as a fully simplified fraction is:

  • \frac{99}{100}\cdot(0.\overline{4})

You must, first, convert     0.\overline{4}    as a fraction.

The line over the decimal 4 means that the digit 4 repeats indefinetly.

To find the fraction that represents this number you follow this procedure:

F=0.\overline 4\\ \\ 10F=4.\overline 4\\ \\ 10F-F=4\\ \\ 9F=4\\ \\ F=4/9

Now, you can mutiply both fractions:

\frac{99}{100}.\frac{4}{9}=\frac{99\times 4}{100\times9}=\frac{11}{25}

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Legalization of marijuana, Part I. The 2010 General Social Survey asked 1,578 US res- idents: \Do you think the use of marijuana
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Answer:

Step-by-step explanation:

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b) For 95% confidence level, z* = 1.96.

\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}= 0.61\pm 0.61\sqrt{\frac{0.61(1-0.61)}{1578}}=0.61\pm 0.024 \ or (0.586, 0.634).

We are 95% confident that the true proportion of US residents who think marijuana should be made legal lies between 58.6% and 63.4%.

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\\np=1578(0.61)=962.58

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Since both np and n(1-p), are at least 10, the normal model is a good approximation for these data.

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2 years ago
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

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then for

P(Y≥ μ+3*σ ) ≥ 0.90

5 0
2 years ago
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