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ohaa [14]
2 years ago
5

An urn contains six chips, numbered 1 through 6. two are chosen at random and their numbers are added together. what is the prob

ability that the resulting sum is equal to 5?
Mathematics
1 answer:
vitfil [10]2 years ago
7 0
<span>2/15 if drawn without replacement. 1/9 if drawn with replacement. Assuming that the chips are drawn without replacement, there are 6 * 5 different possibilities. And that's a low enough number to exhaustively enumerate them. So they are: 1,2 : 1,3 : 1,4 : 1,5 : 1,6 2,1 : 2,3 : 2,4 : 2,5 : 2,6 3,1 : 3,2 : 3.4 : 3,5 : 3,6 4,1 : 4,2 : 4.3 : 4,5 : 4,6 5,1 : 5,2 : 5.3 : 5,4 : 5,6 6,1 : 6,2 : 6.3 : 6,4 : 6,5 Of the above 30 possible draws, there are 4 that add up to 5. So the probability is 4/30 = 2/15 If the draw is done with replacement, then there are 36 possible draws. Once again, small enough to exhaustively list, they are: 1,1 : 1,2 : 1,3 : 1,4 : 1,5 : 1,6 2,1 : 2,2 : 2,3 : 2,4 : 2,5 : 2,6 3,1 : 3,2 : 3,3 : 3.4 : 3,5 : 3,6 4,1 : 4,2 : 4.3 : 4,4 : 4,5 : 4,6 5,1 : 5,2 : 5.3 : 5,4 : 5,5 : 5,6 6,1 : 6,2 : 6.3 : 6,4 : 6,5 : 6,6 And of the above 36 possibilities, exactly 4 add up to 5. So you have 4/36 = 1/9</span>
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mixas84 [53]

Answer:

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x + y = 9.0

subtract x from both sides

y=9-x

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0.50 x +0.20(9-x)= 4.05

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Average number of raisin per slice, λ = 100/45 = 20/9

Hence,

Probability that a randomly chosen slice has no raising :

P(x = 0) = (e^-λ * λ^x) ÷ x!

P(x = 0) = (e^-(100/45) * (100/45)^0) ÷ 0!

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