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1 year ago

7

The sum of Orion and Sagan’s age is 24, and the difference between their ages is 6. Find their ages given that Orion is older th

an Sagan.

1 answer:

Katarina [22]1 year ago

6 0

Let's say that Sagan's age is x and Orion is x + 6 (since Sagan is younger by 6 years).

We know that Orion's age + Sagan's age is 24, so x + x + 6 is 24

2x = 18

x = 9

That means that Sagan is 9, and Orion is 9+6 or 15.

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The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 10 unit

kozerog [31]

Answer:

Step-by-step explanation:

that the triangular prism has more volume

3 0

2 years ago

Which statements are true of the function f(x) = 3(2.5)x? Check all that apply.

Neporo4naja [7]

For this case we have a function of the form:
$y = A * (b) ^ x
$
Where,
A: initial amount
b: growth rate (for b> 1)
x: independent variable
y: dependent variable
We then have the following function:
$f (x) = 3 (2.5) ^ x
$
Using the definition, the following statements are correct:
1) The function is exponential
2) The function increases by a factor of 2.5 for each unit increase in x
3) The domain of the function is all real numbers

8 0

2 years ago

Read 2 more answers

EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi

Valentin [98]

If there is such a scalar function <em>f</em>, then

$\dfrac{\partial f}{\partial x}=4y^2$

$\dfrac{\partial f}{\partial y}=8xy+4e^{4z}$

$\dfrac{\partial f}{\partial z}=16ye^{4z}$

Integrate both sides of the first equation with respect to <em>x</em> :

$f(x,y,z)=4xy^2+g(y,z)$

Differentiate both sides with respect to <em>y</em> :

$\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}$

$\implies\dfrac{\partial g}{\partial y}=4e^{4z}$

Integrate both sides with respect to <em>y</em> :

$g(y,z)=4ye^{4z}+h(z)$

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

$f(x,y,z)=4xy^2+4ye^{4z}+h(z)$

$\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}$

$\implies\dfrac{\mathrm dh}{\mathrm dz}=0$

Integrate both sides with respect to <em>z</em> :

$h(z)=C$

So we end up with

$\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}$

7 0

1 year ago

You used p minutes one month on your cell phone. The next month you used 75 fewer minutes. Simplify the expression.

Anestetic [448]

Hi there!

Let's assume that one month is represented by the variable 'm', the amount of minutes you started with is 's', and minutes you spent is 'p'.

So, one month can be represented as 'm=s-p'.

The next month is a bit more tricky. This will incorporate 75 less minutes into the equation. 'm=s-75' can be used to represent this, as we assume that you didn't use any minutes in the first month, and that p=75 in this case.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)

5 0

2 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

2 years ago