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zheka24 [161]
2 years ago
7

The sum of Orion and Sagan’s age is 24, and the difference between their ages is 6. Find their ages given that Orion is older th

an Sagan.
Mathematics
1 answer:
Katarina [22]2 years ago
6 0

Let's say that Sagan's age is x and Orion is x + 6 (since Sagan is younger by 6 years).


We know that Orion's age + Sagan's age is 24, so x + x + 6 is 24


2x = 18

x = 9


That means that Sagan is 9, and Orion is 9+6 or 15.

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Jane builds a ramp made of a triangular prism and a rectangular prism. What is the volume
Alex787 [66]

Answer:

Correct option: third one ->  11.5 m3

Step-by-step explanation:

To find the volume of the ramp, first we need to find the volume of the rectangular prism and the volume of the triangular prism:

V_rectangular = 4m * 2m * 1m = 8 m3

V_triangular = (2m * 3.5m * 1m) / 2 = 3.5 m3

Now, to find the volume of the ramp, we just need to sum both volumes:

V_total = V_rectangular + V_triangular = 8 + 3.5 = 11.5 m3

Correct option: third one.

6 0
2 years ago
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The number of calls coming per minute into a hotel reservation center is Poisson random variable with mean 3.
natima [27]

Answer:

a) 0.05

b) 0.9826

c) 0.000039308

Step-by-step explanation:

a) P_X(0) = \frac{e^{-3}3^0}{0!} = e^{-3} =  0.05

b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

P_X(0) = e^{-6}

P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}

Hence,

P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826

c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.

P_X(0) = e^{-15}

P_X(1) = e^{15}*15

P_X(2) = \frac{e^{-15}*15^2}{2!} = 112.5*e^{-15}

As a result,

P(X \leq 2) = e^{-15}(1+15+112.5) = 0.000039308

Practically 0

4 0
2 years ago
Round 9,633,202 to the nearest million,
fiasKO [112]

Answer:

10,000,000

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you round up, so that makes it 10,000,000

6 0
2 years ago
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kkurt [141]

We are given that 76 persons can complete the job in 42 days.

We need to find the number of days will 56 persons do the same job.

Let us assume that in x number of days will 56 persons do the same job.

Number of days taken by 1 person to complete same work = 76 × 42 =3192 days.

56 person will take = \frac{3192 }{56} = 57.

<h3>Therefore, 57 days will 56 persons do the same job.</h3>
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One real, rational, Option A

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